"Only variables can be passed by reference"

[AnAmericanGunner]

This is an error I never gotten before, and Googling for my specific problem doesn't seem to help. Maybe if I explain what I am doing without the code someone can figure it out, maybe it's just a change between PHP versions and that's all (from what I've seen at least).

 

I have some variables I want random numbers for, but numbers I chose, so it looks something like this:

$variable = shuffle("1", "5", "10", "15", "20");

 

The first line this appears on is the line that says the error. Am I doing something wrong?

[Drummin]

I'm no expert at arrays, but I think if you print_r($variable); you'll see pointers.  something like [0] => 1, [1] =>5 etc.  And I believe you'll need to access these variables by called or "referencing" the pointer.  Maybe this would work.

$variable = array("1", "5", "10", "15", "20");
print_r($variable);

 

[kenrbnsn]

shuffle takes an array as an argument. It randomizes the content in place, so you want something like:

<?php
$variable = array(1,5,10,15,20);
shuffle($variable);
echo '<pre>' . print_r($variable,true) . '</pre>'; //see what's in the shuffled array
?>

 

Ken

[AnAmericanGunner]

shuffle takes an array as an argument. It randomizes the content in place, so you want something like:

<?php
$variable = array(1,5,10,15,20);
shuffle($variable);
echo '<pre>' . print_r($variable,true) . '</pre>'; //see what's in the shuffled array
?>

 

Ken

 

Once I changed it to this it worked, thanks!