$_POST["file"] not working

[telliott99]

Hi, I have used $_POST with type="text" and for type=" hidden".  I am now using an html form with input type="file"  but I do not get any file name data from the $_POST. 

 

html form has

 

<form name="form" enctype="multipart/form-data" action="sp_ftpupload.php" method="POST" >

<input type = "file"  name = "file" size = "84" accept="text/csv" >

<input type = "submit" value = "Upload" style = "vertical-align:middle" >

</form>

 

php code has

 

$file =  $_POST["file"];

echo "Uploaded file =  ",$file,"<br>";

 

nothing is echo'd.  What am I missing?

[mikesta707]

file data is in the $_FILES super global. not $_POST

[redixx]

You can print_r($_FILES['file']); to see all the information associated with it.

[telliott99]

thanks for the help,    $_FILES is giving the file name.  but ftp_put is not working.  login works and I am connected to the ftp server.  command is

 

$upload = ftp_put($conn_id, $remote_file, $file, FTP_ASCII);

 

uploading a csv file,

tried both ASCII and BINARY ,

tried Passive mode,

verified that hosting company allows ftp uploads

tried providing path name to public-ftp

 

only error message is my own php error message, doesnt say why.  any ideas?  code below.

 

$file =      $_FILES["file"]["name"];

$directory = $_POST["directory"];

echo "directory = ",$directory,"<br>";

include($directory."phud.php");

 

echo "Uploaded file =  ",$file,"<br>";

echo "Save As file =  ",$remote_file,"<br>";

 

print_r($_FILES['file']);

 

// set up basic connection

$conn_id = ftp_connect($ftp_server);

 

// login with username and password

$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass);

 

// check connection

if ((!$conn_id) || (!$login_result)) {

      echo "FTP connection has failed!";

      echo "Attempted to connect to $ftp_server for user $ftp_user_name....";

      exit;

  } else {

      echo "Connected to $ftp_server, for user $ftp_user_name","<br>";

  }

 

// turn passive mode on

ftp_pasv($conn_id, true);

 

// upload the file

$upload = ftp_put($conn_id, $remote_file, $file, FTP_ASCII); 

 

 

// check upload status

if (!$upload) {

      echo "FTP upload has failed!","<br>";

  } else {

      echo "Uploaded $name to $ftp_server ","<br>";

  }

 

if (ftp_put($conn_id, $remote_file, $file, FTP_ASCII)) {

  echo "Successfully uploaded $file\n";}

  else {echo "There was a problem while uploading $file\n";}

 

// close the FTP stream

ftp_close($conn_id);

[kenrbnsn]

What are you trying to do?

 

Also, when posting code, please put your code between

tags.

 

Ken