Reg Expression to match this

[shortysbest]

My url for my website looks like:

 

#/photos&id=1

(in that format for most of the time)

there is one instance that i want it to look like this:

 

#/photos&id=1/#/photo=98

 

but I want to select

the first part, so I can have an if statement saying if #/photos&id=1 changes do this, else if /#/photo=98 changes do this

 

so all I really need help is is with the regexp to match:

 

#/photos&id=1

#/photos&id=1/#/photo=98

 

and that format, both will return:

 

#/photos&id=1

only that

[fugix]

$regexp = '/^.+(\#\/photos\&id\=1)+/i';

[shortysbest]

Thanks, on the right track but I need it to match anything between #/ and /

The variables can change, photos could be profile, and Id could be different

[fugix]

Thanks, on the right track but I need it to match anything between #/ and /

The variables can change, photos could be profile, and Id could be different

ah, okay

$regexp = '/^.+\#\/(\w+\&id\=\d+)\/+/i';

[shortysbest]

Everything between forward slashes should be matched, so if I had #/yshdjdk627:!:&/abc

It would match everything between the fret set of forward slashes. I'm on my phone or else i would try it myself.

 

Thanks

[fugix]

which is what i gave you

[shortysbest]

You have id in there, I'd doesn't always have to be there

[fugix]

You have id in there, I'd doesn't always have to be there

oh okay, misread your post

$regexp = '/^.+\#\/(.+)\/+/i';

[shortysbest]

I just got around to testing that, it doesn't seem to be working. (This is in javascript also, not php)