wazza91 Posted June 17, 2011 Share Posted June 17, 2011 hi im trying to do a insert query but i keep getting the error messeage ? mysql_error() expects parameter 1 to be resource, object given in /Users/garykane/Sites/update2.php on line 6 success in database entry.-1 row inserted? here is my code <?php $con = mysqli_connect("localhost", "root", "") or die ("No connection"); /*connect to server*/ mysqli_select_db($con ,"Declan") or die ("db will not open"); /*connect to database*/ $dno = $_POST["dno"]; $dname = $_POST["dname"]; $location = $_POST["location"]; $query="Update INTO AccountNumber VALUES (" .$dno . ", '" . $dname . "','" . $location . "')"; if(!mysqli_query($con, $query)) echo mysql_error($con); echo "success in database entry."; $numrows = mysqli_affected_rows($con); echo $numrows . " row inserted<br>"; mysqli_close($con); ?> here is the front end texbox code <html> <head> <title>Question 2, Accounts</title> </head> <h1>Enter Details</h1> <body> <form action="update2.php" method="post"> Account Number : <input type="text" name="dno" /><br /> Balance : <input type="text" name="dname" /><br /> Customer Name : <input type="text" name="location" /><br /> <input type="submit" name="submit" value="submit" /> </form> <?php $con = mysqli_connect("localhost", "root", "") or die ("No connection"); /*connect to server*/ mysqli_select_db($con ,"Declan") or die ("db will not open"); /*connect to database*/ ?> </body> </html> Quote Link to comment Share on other sites More sharing options...
Nodral Posted June 17, 2011 Share Posted June 17, 2011 Where do you actually execute the query? you seem to be missing a mysqli_query line Quote Link to comment Share on other sites More sharing options...
mikosiko Posted June 17, 2011 Share Posted June 17, 2011 just for a start ... im trying to do a insert query ??? INSERT is not the same as UPDATE $query="Update INTO AccountNumber VALUES (" .$dno . ", '" . $dname . "','" . $location . "')"; if(!mysqli_query($con, $query)) echo mysql_error($con); Quote Link to comment Share on other sites More sharing options...
facarroll Posted June 17, 2011 Share Posted June 17, 2011 Should that be "' .$dno . '" and not " .$dno . " ? Quote Link to comment Share on other sites More sharing options...
redixx Posted June 17, 2011 Share Posted June 17, 2011 You are using mysql_error when you should be using mysqli_error. mysqli_error($con); Also your query is wrong. Instead of Update INTO you need INSERT INTO. Quote Link to comment Share on other sites More sharing options...
PFMaBiSmAd Posted June 17, 2011 Share Posted June 17, 2011 Edit: too slow on the submit button, see the same information above ^^^ You also need the i on the mysqli_error($con) statement since you are using mysqli for the connection, query, close... Quote Link to comment Share on other sites More sharing options...
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