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Assuming the two tables have are exactly the same (i.e., has the same attributes), then the

classical Relational MINUS ought to do the trick.

 

A MINUS B, would return the records of A that are not found in B.

 

However, since that is not supported in SQL, you can simulate it using

WHERE EXISTS, like so:

 

   SELECT * FROM nightly_feed 
   WHERE NOT EXISTS(
        SELECT * FROM
        apps
            WHERE apps.field1 = nightly_feed.field1 AND apps.field2 AND nightly_feed.field2 (AND ..etc..) 
   )

 

In short, use every attribute of the two tables/relvars.

 

 

Hope it helps.

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