jrtime Posted June 24, 2011 Share Posted June 24, 2011 I had a simple php page, that I think was written in php 3 that would only display a page if a user had logged on: session_start(); $username = "bob"; if ($_SESSION['user'] != $username) {?> <?php echo "You must logon."; echo "<a href='login.php'>Logon<a/>; ?> <?php } else} ?> <html> </html> <?php } ?>[code] This worked fine till the server was updated to only accept php 5(Server information shows PHP Version: 5.2.12). Now, I am getting a parse error: Parse error: syntax error, unexpected '}' , which is the } in the following section: [code]<?php } else [code] I ran the page through syntax checkers for php 5, and it it showing up as coded okay, but it is not working. Can anyone see what I am doing wrong or need to updated to make this work? Thanks! Quote Link to comment Share on other sites More sharing options...
Nuv Posted June 24, 2011 Share Posted June 24, 2011 <?php session_start(); $username = "bob"; if ($_SESSION['user'] != $username) {?> <?php echo "You must logon."; echo "<a href='login.php'>Logon<a/>; ?> <?php } else{ // You need to start { and not close } here ?> <html> </html> <?php } ?> In <?php } else} ?> it should be <?php } else { ?> Quote Link to comment Share on other sites More sharing options...
trq Posted June 24, 2011 Share Posted June 24, 2011 It's missing the opening <?php tags. Quote Link to comment Share on other sites More sharing options...
jrtime Posted June 28, 2011 Author Share Posted June 28, 2011 That worked great. I guess it has been wrong for some time and the older php on the server had been more forgiving. Thanks again. Quote Link to comment Share on other sites More sharing options...
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