Jump to content

Update one table based on another table


deansatch

Recommended Posts

I have 2 tables, one for products (which includes ALL products and stock quantities) and one for picking lists (basically a shopping cart)

 

When the query is submitted, I want it to get the quantities from 'pickingLists' table for each of the products in that query, and update the quantities of those products in the 'products' table. At the moment, what I have does exactly that, but it also sets the qty of every other product as 0. I just want it to perform the update on the relevant rows, not all of them.

 

mysql_query("UPDATE products t1 SET  qty = qty-(SELECT qty FROM pickingLists t2 WHERE t2.productName = t1.productName AND t1.size= t2.size AND  t2.listID = '$listID')") or die(mysql_error());

 

Where am I going wrong?

Link to comment
Share on other sites

You need to have another WHERE outside your SELECT to tell the update which record it is to update, otherwise it will, as you have found out, update every record.

ysql_query("UPDATE products t1 SET  qty = qty-(SELECT qty FROM pickingLists t2 WHERE t2.productName = t1.productName AND t1.size= t2.size AND  t2.listID = '$listID')   WHERE table.value = uniqueIdentifier   ") or die(mysql_error());

Link to comment
Share on other sites

That's what I thought, but when I add the similar WHERE outside the select, it doesn't seem to recognise the pickingList table:

 

mysql_query(
"UPDATE products t1 SET  qty = qty-(SELECT qty FROM pickingLists t2 
WHERE t2.productName = t1.productName AND t1.size= t2.size AND t1.colour = t2.colour AND t2.listID = '$listID') 
WHERE t2.productName = t1.productName AND t1.size= t2.size AND t1.colour = t2.colour") or die(mysql_error());

 

I get error: Unknown column 't2.productName' in 'where clause'

Link to comment
Share on other sites

Thanks...I have just got it working though.

 

mysql_query("UPDATE products t1 ,pickingLists t2
SET  t1.qty = t1.qty-(SELECT t2.qty FROM pickingLists t2 WHERE t2.productName = t1.productName AND t1.size= t2.size AND t1.colour = t2.colour AND t2.listID = '$listID') 
WHERE t2.productName = t1.productName AND t1.size= t2.size AND t1.colour = t2.colour") or die(mysql_error());

 

This seems to work...hopefully it's not flawed!

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.