Simple user log-in script error

[garethuk]

Hi all,

 

I have a basic member login script working on my website.

 

Currently, if the user isn't logged in they cannot see certain pages and get redirected to access-denied.php by the following script:

<?php
//Start session
session_start();

//Check whether the session variable SESS_MEMBER_ID is present or not
if(!isset($_SESSION['SESS_MEMBER_ID']) || (trim($_SESSION['SESS_MEMBER_ID']) == '')) {
	header("location: access-denied.php");
	exit();
}
?>

 

However, I am trying to amend this code so that if the user isn't logged in they can see the page but cannot see various elements of the page. Therefore, instead of sending a user to the access-denied.php page, I want to set a variable in the above code which I can then compare with elsewhere on the page (to decide whether to show a certain paragraph for example).

 

I have got this far...

<?php
//Start session
session_start();

//Check whether the session variable SESS_MEMBER_ID is present or not
if(!isset($_SESSION['SESS_MEMBER_ID']) || (trim($_SESSION['SESS_MEMBER_ID']) == '')) {
	$logged_in = "no";	}
?>

 

As a test to see if it works I then put the following later in the file...

<?php if ($logged_in = "no") echo 'Not logged into website'; else echo 'Logged into website'; ?>

 

However, the output always comes through as "Not logged into website", even though I have logged in.

 

Can anybody see what the problem is?

[trq]

You use == to compare values in php, not =

[garethuk]

That was quick!

 

Thanks so much, that solved it.

[Clarkeez]

When I was learning the basics, this page helped me greatly.

Check it out http://www.w3schools.com/php/php_operators.asp