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Hello, how are you?

 

I'm having some problems when procesing a text input parameter via ajax.

 

This are my codes:

 

ajax.js

function objetoAjax(){
var xmlhttp=false;
try {
	xmlhttp = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
	try {
	   xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
	} catch (E) {
		xmlhttp = false;
  		}
}

if (!xmlhttp && typeof XMLHttpRequest!='undefined') {
	xmlhttp = new XMLHttpRequest();
}
return xmlhttp;
}

function MostrarConsulta(data){
divComentarios = document.getElementById('comments');
ajax=objetoAjax();
ajax.open("POST", data);
ajax.onreadystatechange=function() {
	if (ajax.readyState==4) {
		divComentarios.innerHTML = ajax.responseText
	}
}
ajax.send(null)
}

 

video.php

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">  
<html xmlns="http://www.w3.org/1999/xhtml">  
<head>  
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />  
<link href="estilo.css" rel="stylesheet" type="text/css" media="screen" />  
<script language="JavaScript" type="text/javascript" src="ajax.js"></script> 

<?php   
    (isset ($_GET['id']))? $id = $_GET['id'] : $id = NULL;        
        session_start();   
    function connext($host,$user,$password,$BBDD){   
       $link=mysql_connect($host,$user,$password) or die (mysql_error());   
       mysql_select_db($BBDD,$link) or die (mysql_error());   
       return $link;   
    }   

$link=conectarse("host","user","password","database");    

$video = "SELECT * FROM `videos` WHERE `video_id` = '$id'";  
$video = mysql_query($video, $link);   

$comment1 = "select comment_id, comment, name, lname from video_comments, users where video_comments. user_id = users.user_id and video_id = '$id' order by 1 desc";  
$comment1 = mysql_query($comment1, $link);   

?>   
<title>Videos</title>  
</head>  
<div id="video">  
        <?php   
          $rs=mysql_fetch_array($video);  
            echo      "<object style='height: 200px; width: 400px'>"  
                    ."<param name='movie' value='http://www.youtube.com/v/" .$rs['url']. "'>"  
                    ."<param name='allowFullScreen' value='true'>"  
                    ."<param name='allowScriptAccess' value='always'>"  
                    ."<embed src='http://www.youtube.com/v/" .$rs['url']. "' type='application/x-shockwave-flash' allowfullscreen='true' allowScriptAccess='always' width='640' height='390'>"  
                    ."</object>";  
        ?>  
</div>  


<div id="comments">  
    <?php  
        while($rs=mysql_fetch_array($comment1))   
          {   
            echo         "" .$rs['name']. " " .$rs['lname']. ": " .$rs['comment']. "<br />";  
          }   
    ?>  
</div>  


<div id="add_comments">  
    <form action="" onsubmit="MostrarConsulta('add_comment.php'); return false"> 
    <input type="text" name="comment" value="" /> 
    <input type="text" name="id" value="40" /> 
    <input type="submit" value="Add" /> 
    </form> 
</div>  
</body>  
</html>

 

add_comment.php:

<?php  
session_start();   

$con = mysql_connect("host","user","password");  

if (!$con)  
  {  
  die('Could not connect: ' . mysql_error());  
  }  

mysql_select_db("database", $con);  

$comment2="INSERT INTO video_comments (comment_id, user_id, video_id, comment)  
VALUES  
('','$_SESSION[user]','$_POST[id]','$_POST[comment]')";  

if (!mysql_query($comment2,$con))  
  {  
  die('Error: ' . mysql_error());  
  }  

mysql_close($con);  

?>

 

 

When I add a comment with the add_comment.php, it doesnt recognise the values of $_POST[id] and $_POST[comment], how do I do to ask the values of the text inputs (id and comment) of the video.php with add_comment so that it recognise the values?

 

This are the errors I get:

 

Notice: Undefined index: id in C:\xampp\htdocs\add_comment.php on line 15

 

Notice: Undefined index: comment in C:\xampp\htdocs\add_comment.php on line 15

 

Thank you a LOT for your help!

I'm not getting any Javascript errors, the only errors that I get are because add_comment.php does not recive the id, comment values:

 

Notice: Undefined index: id in C:\xampp\htdocs\add_comment.php on line 15

 

Notice: Undefined index: comment in C:\xampp\htdocs\add_comment.php on line 15

 

Someone told me that I'm not sending any value to the MostrarConsulta(data), I'm just sending the add_comment.php, I need to concatenate the values and send them via MostrarConsulta(), how do I do that? I have no idea.

 

Um - hopefully this will help:

 

1. In your AJAX, you have used:

 

ajax.open("POST", data);

 

it should be:

 

ajax.open("POST", url);

 

also you have used:

 

ajax.send(null)

 

when it should be:

 

ajax.send(data)

 

You should be sending data when it;s a POST with ajax.send

 

Wanna try that and let me know how you get on?

It doesnt show me any error, it means that it doesnt even read the add_comment.php because I got no php errors, also, it doesnt add anything to the database, not even blank spaces.

 

I think that I need to send the text-input values with the form. The ajax.js needs to recive the input-text values and send them to the add_comment.php via MostrarConsulta().

 

Thank you a lot for your help!

Yes, I did all that!

 

I will translate what I got from http://www.forosdelweb.com/f77/problemas-con-valor-del-text-input-procesar-php-937835/#post3964510:

 

"On which part you send those 2 text-input values (id and comment from video.php) that I dont see?. The only thing that you send to the function MostrarConsulta is the url add_comment.php but by nowhere you pass the values. You have to concatenate the 2 variables and its values."

 

Any clues?

 

Thanks!

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