csabi_fl Posted October 20, 2006 Share Posted October 20, 2006 Hello there.I use the following code to output data on one of my webpages:<?phpmysql_pconnect("localhost","",""); mysql_select_db(""); $query = "SELECT loginid,SUM(week1+week2) AS weekSum FROM submit1 GROUP BY loginid ORDER BY weekSUM DESC";$result = mysql_query($query);while ($list = mysql_fetch_array($result)) { echo "{$list['loginid']}|{$list['weekSum']}<br>";}?>It looks something like:John|70Michael|65Bill|60and so on.I would like to align it so that the numbers are in 1 column as well.I know I need padding but I don't know the syntax.Also I want to add a column with order numbers:1)John|702)Michael|65 3)Bill|60....I am a newbie so PLEASE explain.Thank you in advance. Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/ Share on other sites More sharing options...
alpine Posted October 20, 2006 Share Posted October 20, 2006 I have to admit i'm not fully aware of what exactly you are asking for, but here is a example with a line-counter:[code]<?phpecho <<<_HTML<table cellpadding="5" cellspacing="0" border="1"><tr> <td>No.</td><td>Login ID</td><td>Weeksum</td></tr>_HTML;mysql_pconnect("localhost","","");mysql_select_db("");$query = "SELECT loginid,SUM(week1+week2) AS weekSum FROM submit1 GROUP BY loginid ORDER BY weekSUM DESC";$result = mysql_query($query);$counter = 1;while ($list = mysql_fetch_array($result)){$login_id = $list['loginid'];$weeksum = $list['weekSum'];echo <<<_HTML<tr> <td>$counter</td><td>$login_id</td><td>$weeksum</td></tr>_HTML;$counter++;}echo "</table>";?>[/code] Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-112081 Share on other sites More sharing options...
csabi_fl Posted October 25, 2006 Author Share Posted October 25, 2006 Hi.That is exactly what I needed it.Thank you.I have one more question.Out of this table how do I output a row on another page?For example:3| Peter|50 (this is one row in the table)How do I output on another page that Peter is in 3. position?Or that Peter has 50 points?Could you help me with the code? Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-114222 Share on other sites More sharing options...
csabi_fl Posted October 26, 2006 Author Share Posted October 26, 2006 Rookie needs help here.PLEASE read previous posts.Very urgent. Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-114742 Share on other sites More sharing options...
Orio Posted October 26, 2006 Share Posted October 26, 2006 [code]<?php//Connect to DB here$result= mysql_query("SELECT * FROM `TABLE_NAME` WHERE Col_name='Peter'");$row=mysql_fetch_array($result);echo $row['Col_Points']."<br>".$row['Col_Position'];?>[/code]Just change the table and the column names to the ones in your database.Orio. Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-114767 Share on other sites More sharing options...
csabi_fl Posted October 26, 2006 Author Share Posted October 26, 2006 [code]Please take a look at this code:[code<?phpecho <<<_HTML<table cellpadding="5" cellspacing="0" border="1"><tr> <td>No.</td><td>Login ID</td><td>Weeksum</td></tr>_HTML;mysql_pconnect("localhost","","");mysql_select_db("");$query = "SELECT loginid,SUM(week1+week2) AS weekSum FROM submit1 GROUP BY loginid ORDER BY weekSUM DESC";$result = mysql_query($query);$counter = 1;while ($list = mysql_fetch_array($result)){$login_id = $list['loginid'];$weeksum = $list['weekSum'];echo <<<_HTML<tr> <td>$counter</td><td>$login_id</td><td>$weeksum</td></tr>_HTML;$counter++;}echo "</table>";?>][/code]It outputs a table on one of my pages.It works great.My question is:How do I change this code so it will output only certain rows.For example one row in this table looks like:34|Paul|120 points.When Paul logs in I want to show that his position in the table is 34.How do I change the above code to do just that? Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-114955 Share on other sites More sharing options...
Orio Posted October 26, 2006 Share Posted October 26, 2006 You need to add a condition between "...FROM submit1" to "GROUP BY...". Example:SELECT loginid,SUM(week1+week2) AS weekSum FROM submit1 [b]WHERE username='$username'[/b] GROUP BY loginid ORDER BY weekSUM DESCSee more [url=http://www.w3schools.com/sql/sql_where.asp]here[/url].Orio. Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-114958 Share on other sites More sharing options...
csabi_fl Posted October 26, 2006 Author Share Posted October 26, 2006 I don't get it.I changed the code like you said and it pulls one row out of the table,BUT the first column(counter) is 1 for every member.So I believe there is something wrong in the 'echo' statement.Could you take a look at that,please? Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-115001 Share on other sites More sharing options...
csabi_fl Posted October 27, 2006 Author Share Posted October 27, 2006 Hi guys.Please read my previous posts and help me out here.It is very URGENT.Thank you. Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-115339 Share on other sites More sharing options...
csabi_fl Posted October 27, 2006 Author Share Posted October 27, 2006 Hi. Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-115530 Share on other sites More sharing options...
sasa Posted October 27, 2006 Share Posted October 27, 2006 use two queries1st [code]SELECT loginid,SUM(week1+week2) AS weekSum FROM submit1 WHERE username='$username' GROUP BY loginid ORDER BY weekSUM DESC[/code] 2nd from position[code]SELECT COUNT(*)+1, SUM(week1+week2) AS weekSum FROM submit1 WHERE weekSum > $weeksum GROUP BY loginid ORDER BY weekSUM DESC[/code] Link to comment https://forums.phpfreaks.com/topic/24594-how-to-initialize-a-php-variable/#findComment-115584 Share on other sites More sharing options...
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