Jump to content


Photo

VERY SIMPLE QUESTION Converting data


  • Please log in to reply
1 reply to this topic

#1 stewart715

stewart715
  • Members
  • PipPipPip
  • Advanced Member
  • 58 posts

Posted 21 October 2006 - 07:04 AM

I need to a script that will do this in the following order
1.  connect to a db
2.  select PID from tableb where UID=$user->uid (current user)
3.  if PID =1 print YES if PID=2 print NO

any suggestions?

#2 .josh

.josh
  • Staff Alumni
  • .josh
  • 14,871 posts

Posted 21 October 2006 - 07:38 AM

<?php
   // 1. connect to a db
   $conn = mysql_connect('localhost','username','password') or die(mysql_error());
   $db = mysql_select_db('dbname',$conn) or die(mysql_error());
  
   // 2. select info
   $id = $user->uid;
   $sql = "select PID from tableb where UID=$id";
   $result = mysql_query($sql, $conn) or die(mysql_error());

   // 3. print yes or no
   $yesorno = mysql_fetch_assoc($result);
   switch ($yesorno[0]) {
      case 1 : echo "yes"; break;
      case 2 : echo "no"; break;
      default : echo "1 or 2 not found..some kind of error";
   }
?>

Did I help you? Feeling generous? Buy me lunch! 
Please, take the time and do some research and find out how much it would have cost you to get your help from a decent paid-for source. A "roll-of-the-dice" freelancer will charge you $5-$15/hr. A decent entry level freelancer will charge you around $15-30/hr. A professional will charge you anywhere from $50-$100/hr. An agency will charge anywhere from $100-$250/hr. Think about all this when soliciting for help here. Think about how much money you are making from the work you are asking for help on. No, we do not expect you to pay for the help given here, but donating a few bucks is a fraction of the cost of what you would have paid, shows your appreciation, helps motivate people to keep offering help without the pricetag, and helps make this a higher quality free-help community :)




0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users