Using two functions in one echo?

[likeskoolaid]

I have two functions, one turns un-href links into working href links.

 

 

<?php
$reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";
?>

 

 

The other replaces an array of words into a different word.

 

 

<?php
$replace = array(
'Cat' => 'Dog',
);
?>

 

 

This is how you echo both separately, the problem I'm having and need help with is combining both functions into one echo so both fixes apply to a single variable ($content).

 

 

<?php echo str_replace_assoc($replace,$content); ?>

<?php echo preg_replace(a$reg_exUrl, '<a href="'.$url[0].'" target="_blank" class="outboundlink" rel="nofollow">'.$url[0].'</a>', $content); ?>

 

[Pikachu2000]

You mean like this?

<?php
$content = str_replace_assoc($replace,$content);
echo preg_replace(a$reg_exUrl, '<a href="'.$url[0].'" target="_blank" class="outboundlink" rel="nofollow">'.$url[0].'</a>', $content);
?>

[likeskoolaid]

Thank you for answering.

 

Will your code still work if I'm using $content as a variable previously in the script? like

 

$content='hello';

 

 

[Pikachu2000]

I don't see any reason it shouldn't, you're just reassigning the resulting output to the variable.

[likeskoolaid]

You notice any errors in your code?

 

Parse error: syntax error, unexpected T_VARIABLE in

 

[Pikachu2000]

Looks like there's an 'a' that doesn't belong in there. It was in the code in the OP too, all I did was copy/paste it ...