studgate Posted September 5, 2011 Share Posted September 5, 2011 hey guys, I am having a small problem and I can't wrap my head around it. I want users to be able to upload up 10 photos in the database and what I want to do is check the database to see how many pics they have already and if they have 10, just show the photo with action items but if they have 7 for example, show the 7 pictures and three upload fields, if they have 4, show the pics and 6 fields and so on... let me know what you guys think and some help. Thanks in advance guys, you always come through... Quote Link to comment https://forums.phpfreaks.com/topic/246480-list-and-show-inputs-based-on-database-count/ Share on other sites More sharing options...
codefossa Posted September 5, 2011 Share Posted September 5, 2011 $result = mysql_query($sql); while ($row = mysql_fetch_assoc($result)) { echo '<img src="' . $row['image_url'] . '" />'; } for ($i = 0; $i < (10 - mysql_num_rows($result)); $i++) { echo '<input type="" name="" />'; } echo '<input type="submit" />'; Quote Link to comment https://forums.phpfreaks.com/topic/246480-list-and-show-inputs-based-on-database-count/#findComment-1265678 Share on other sites More sharing options...
studgate Posted September 5, 2011 Author Share Posted September 5, 2011 thanks Kira for getting in the right direction, i know what I have to do now plus your code works fine, just need to modified to fill my needs. Quote Link to comment https://forums.phpfreaks.com/topic/246480-list-and-show-inputs-based-on-database-count/#findComment-1265680 Share on other sites More sharing options...
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