Regex for two digit number 18 or over

[giraffemedia]

hello,

 

I'm trying to put together a regex that validates a two-digit number if it's over 17 i.e. 18 of more.

 

Can anyone help, i'm not terribly hot on regex stuff.

 

Thanks,

 

James

[giraffemedia]

No worries i've just figured it out.

 

It's [1-9][8-9]

 

James

[salathe]

What about 20, 21, 22, 23, 24, 25, 26, 27, 30, 31, 31, 33, 34... ?

[The Little Guy]

This might work (might as in I don't know how your using the number).

<?php
$values = array(
"Joe is 18 years old",
"Joe is 13 years old",
"Joe is 11 years old",
"Joe is 100 years old"
);
foreach($values as $value){
preg_match("/\d+/", $value, $matches);
if($matches[0] >= 18){
	echo "Joe is 18 or older";
}else{
	echo "Joe is under 18";
}
echo "<br>";
}
?>

 

 

if you have as specific number, such as $age = 10, then you could just do something like this:

 

$age = 10;
if($age >= 18){
echo "18 or older";
}else{
echo "under 18";
}

[xyph]

1[89]|[2-9]\d

Match either the regular expression below (attempting the next alternative only if this one fails) «1[89]»
   Match the character “1” literally «1»
   Match a single character present in the list “89” «[89]»
Or match regular expression number 2 below (the entire match attempt fails if this one fails to match) «[2-9]\d»
   Match a single character in the range between “2” and “9” «[2-9]»
   Match a single digit 0..9 «\d»

[Pikachu2000]

If it's just a number and nothing else, you don't even really need a pattern. This should be faster too.

 

if( ctype_digit($number) && $number > 17 && $number < 100 ) {

[The Little Guy]

If it's just a number and nothing else, you don't even really need a pattern. This should be faster too.

 

if( ctype_digit($number) && $number > 17 && $number < 100 ) {

 

personally I don't like that. I would have done this:

 

if((int)$number > 17) {

[salathe]

if( ctype_digit($number) && $number > 17 && $number < 100 ) {

 

if((int)$number > 17) {

 

 

$number = "00000000000000000000000000000000000000000000042"; 

[Pikachu2000]

&& strlen == 2 rather than $number < 100

[The Little Guy]

if( ctype_digit($number) && $number > 17 && $number < 100 ) {

 

if((int)$number > 17) {

 

 

$number = "00000000000000000000000000000000000000000000042"; 

 

They both worked...