class help Notice: Undefined variable: layout in

[mrooks1984]

hello all, i have ran into another issue i get this message when i go onto my homepage

 

Notice: Undefined variable: layout in

 

i have the following includes on the main index page:

 

<?php
// Include Main Core File.
include '_class/core.php';

// Include Config File
include 'config/config.php';
include 'config/db.php';

// Use Database
$obj->connect();

// Include library
include '_class/library.php';

// Include layout
include 'layout/index.php';
?>

 

on the config file i have the varible it is refering too:

 

<?php
$layout = $url . "layout/";
?>

 

the actual file i get the error on (library.php)

<?php

class library extends core {

function advert() {

	/* 
	* Name your images 1.jpg, 2.jpg etc. 
	* 
	* Add this line to your page where you want the images to 
	* appear: <?php include "randomimage.php"; ?> 
	*/ 

	// Change this to the total number of images in the folder 
	$total = "2"; 

	// Change to the type of files to use eg. .jpg or .gif 
	$file_type = ".png"; 

	// Change to the location of the folder containing the images 
	$image_folder = $layout . "layout/images/adverts"; 

	// You do not need to edit below this line 

	$start = "1"; 

	$random = mt_rand($start, $total); 

	$image_name = $random . $file_type; 

	echo "<img src=\"$image_folder/$image_name\" alt=\"$image_name\" />";
}
}

$obj = new library;


?>

 

is there a way to make it so it $layout works on any page or file as long as its in the includes?

 

thanks again.

[trq]

Your asking to make $layout some sort of global variable which completely breaks the entire idea of using a class.

 

If your class really depends on the $layout variable, it should be passed into the objects __construct().

[mrooks1984]

thanks for your help, could you please show me how i would do your surgestion.

 

thanks.

[trq]

<?php

class something {
  private $somevar;
  
  public function __construct($somevar)
  {
    $this->somevar = $somevar;
  }

  public function test()
  {
    return $this->somevar;
  }
}

$layout = 'foo';
$obj = new something($layout);
echo $obj->test();