Using is_int

[SlinkyABC]

Hi,

 

I did a search for this function and found a similar post but wasn't able to understand it.

 

Presently I am just trying to do a simple test with the is_int function. I have it set up as follows:

 

if (is_int ($variable)) {
          echo 'Integer';
          } else {
          echo 'Not integer';

 

$variable is converted to a variable from some text on a web form.

 

I can see the problem here is that no matter what is entered on the web form, $variable is always a string. The code I referenced above works fine if I instead use the is_string function. I guess I'm just trying to figure out the following:

 

1. Why is it always a string, even when entering a number such as 7?

2. How can I overcome this so that I can check to make sure the input is of the correct type (integer)?

 

I know I'm probably not doing a good job of explaining what I mean but I think what I'm aiming to do should be clear; let me know if it isn't.

 

 

NOTE--I think I get this to a degree--anything passed in a form will be a string, is that correct? So I should be able to use is_numeric instead. However, the problem with that is that it would also return True for non-integers such as floats. I only want the user to be able to enter integers, 8.5 should return False in this case.

 

Thanks!

 

 

[Nodral]

Try using this function

function is_really_int(&$val) {
        $num = (int)$val;    
        if ($val==$num) {
            $val=$num;
            return true;
        }
        return false;
    }

 

Loads more information here http://php.net/manual/en/function.is-int.php

[silkfire]

is_int will only return true if the variable has the internal type int, not if it's a mathematical integer.

 

You should use some for of RegEx I think.

[cyberRobot]

Have you looked into ctype_digit?

http://php.net/manual/en/function.ctype-digit.php