ukscotth Posted November 8, 2011 Share Posted November 8, 2011 Hi all, I have the following : print_r($fqlResult); Which gives the following result : Array ( [0] => Array ( [src_big] => http://a5.sphotos.ak.fbcdn.net/hphotos-ak-ash4/299117_2121699756933_1079004376_2442101_3103384_n.jpg ) ) I want to grab just the image url from it and store it in a seperate variable. Any ideas how I can do this plzzz ? Thanks in advance, Scott. Link to comment https://forums.phpfreaks.com/topic/250743-getting-a-certain-part-of-an-array/ Share on other sites More sharing options...
xyph Posted November 9, 2011 Share Posted November 9, 2011 Read the manual? $fqlResult[0]['src_big'] Link to comment https://forums.phpfreaks.com/topic/250743-getting-a-certain-part-of-an-array/#findComment-1286440 Share on other sites More sharing options...
Pikachu2000 Posted November 9, 2011 Share Posted November 9, 2011 You know the array's structure from the output of print_r(), so what else is it you need to know? Link to comment https://forums.phpfreaks.com/topic/250743-getting-a-certain-part-of-an-array/#findComment-1286441 Share on other sites More sharing options...
ukscotth Posted November 9, 2011 Author Share Posted November 9, 2011 Thanks. I did read the manual but im new to using arrays so it didnt make much sense to me. Thanks again. Link to comment https://forums.phpfreaks.com/topic/250743-getting-a-certain-part-of-an-array/#findComment-1286444 Share on other sites More sharing options...
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