IF is file print all others

[m_tyhurst2002]

Hello guys and gals, I am pretty green to PHP! I have an empty array that that I am trying to put images into. The thing is I have a certain file name in the folder, I want to exclude that file. This is what I have tried, any advice would be appreciated!

 

$thumbImg[] = array();
foreach (glob($DImg) as $PImg)
{
	if (!is_file("thumbnail.jpg"))
	{
		$thumbImg[] = "<img src=\"pathtoimage\">";
	}
}

 

Later on the page I am printing it out with this. It is still including the thumbnail.jpg image. Thank you in advance!!

 

for ($i=0; $i<count($thumbImg); $i++)
print $thumbImg[$i];

[Adam]

is_file will check if the file exists on the server, nothing related to the current file in your array. You need to compare it directly:

 

if (basename($PImg) != 'thumbnail.jpg')
{
    // ...
}

 

Though if you plan on expanding this list, you might want to create an array of exceptions and then check the current file in your loop is not within the exceptions array:

 

$exceptions = array(
    'thumbnail.jpg',
    'another-file.jpg'
);

[...]

if (!in_array(basename($PImg), $exceptions))
{
    // ...
}

 

Edit

 

Define your exceptions array before the loop by the way.

[m_tyhurst2002]

Awesome, thank you very much!! It works beautifully with the $exceptions array. I do have one more question. Where I am printing the FOR loop, it outputs the word "array" right before the images. Is the loop incorrect somehow? Thank you so much for your help!

 

<?
for ($i=0; $i<count($thumbImg); $i++)
	print $thumbImg[$i];
?>

[Adam]

What does the following code display..?

 

	for ($i=0; $i<count($thumbImg); $i++)
	var_dump($thumbImg[$i]);

[m_tyhurst2002]

It outputs, "array(0) { } string(192) " " string(192) " " string(192) "", along with the images. Thanks for the quick reply!!

[m_tyhurst2002]

The empty array was wrong. Instead of this,

 

$thumbImg[] = array();

 

It's supposed to be,

 

$thumbImg = array();

 

Thanks for your help Adam!!