$_POST problem

[adv]

hello i have a script and i keep getting an error

on php4 i dont get that error

only on php5

<?php
session_start();
error_reporting(E_ALL);
ini_set('display_errors',1);
function query_str($params) {
        $str = '';
                foreach ($params as $key => $value) {
                        $str .= (strlen($str) < 1) ? '' : '&';
                        $str .= $key . '=' . rawurlencode($value);
                }
                 return ($str);
}

if($_GET['id']=='1'){
                $query=parse_str($_POST);
                query_str($query);
                $username=rtrim($username);
                $password=rtrim($password);
                // .... continue
echo $username.':'.$password.chr(10);
}

 

Warning: parse_str() expects parameter 1 to be string, array given in /var/www/poo/do.php on line 15 
Warning: Invalid argument supplied for foreach() in /var/www/poo/do.php on line 7 
Notice: Undefined variable: username in /var/www/poo/do.php on line 17 
Notice: Undefined variable: password in /var/www/poo/do.php on line 18 

 

the html code is this

<form  name="Form_Auth" action="do.php?id=1" method="post" target="_top">
<input name="username" id="txt" value="Nome utente" class="nomeutente">
<input name="password" type="password" maxlength="32" id="pass" value="password" class="password lf">
<input name="bottone" type="submit" class="bottone rf" value="Invia" alt="accedi">
</form>

[trq]

$_POst is an array. As the name suggests parse_str expects a string.

 

This is no different between php4 - 5, it is likely that your php4 install is misconfigured to hide errors form you the developer.

[SergeiSS]

It's not a POST problem! It means that you can't read in English

What is written?

"parse_str() expects parameter 1 to be string, array given" - what is POST? It's an array. PHP is right, you give to the function parse_str() an array instead of string.

"Invalid argument supplied for foreach()" is also correct because you send $query to this function and suppose it's an array. But why are you sure that it's an array?

[adv]

i have a php 4.3 server and it worked like that

but i figure it out anyway

 

 

  $str = '';
                foreach ($_POST as $key => $value) {
                        $str .= (strlen($str) < 1) ? '' : '&';
                        $str .= $key . '=' . rawurlencode($value);
			}
                parse_str($str);

[trq]

  Quote

i have a php 4.3 server and it worked like that

 

No, your php4.3 server was configured to hide errors from you. Bad code is bad code, it doesn't matter what version it is written in.

[adv]

yea thanks alot i got it now:D