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Insert into error


regoch
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Hail!

I got this script for insert message in my guestbook. But it wont insert any data in rows. Error checking is working, I even echo every variable to test it, try to manualy test code in mysql myadmin and everything working fine. So variables are ok, mysql code is ok, but script wont insert anything in rows. Any ideas?

<?php

error_reporting (E_ALL ^ E_NOTICE);

$post = (!empty($_POST)) ? true : false;

if($post)
{

$name = stripslashes($_POST['name']);
$email = trim($_POST['email']);
$message = stripslashes($_POST['message']);
$sigureca = $_POST['sigureca'];
$error = '';

//provjera imena
if(empty($name))
{
$error .= '<strong>Molimo upišite ime.</strong><br />';
}
//checks for an email
if (empty($email)) {
$error .= '<strong>Molimo upišite e-mail.</strong><br />';
} else {
	if (!eregi ('^[[:alnum:]][a-z0-9_\.\-]*@[a-z0-9\.\-]+\.[a-z]{2,4}$', stripslashes($email))) {
	$error .= '<strong>Molimo upišite ispravan e-mail.</strong><br />';
} // if eregi
} // if empty email

//provjera poruke
if(empty($message) || strlen($message) < 15)
{
$error .= "<strong>Molimo upišite poruku. Mora imati bar 15 znakova.</strong><br />";
}
//provjera šigurece
if($sigureca <> "H6F7N1")
{
$error .= "<strong>Kod nije ispravan.</strong>";
}


if(!$error)
{
$visitorIP = getenv("HTTP_X_FORWARDED_FOR");
		if (($visitorIP == null) or ($visitorIP == ""))
		{
		$visitorIP = getenv("REMOTE_ADDR");
		} 
		else
		{
		list ($proxyIP, $visitorIP) = split ('[,]', $visitorIP);
		$visitorIP = ltrim($visitorIP);
		}
$datum = date('Y-m-d');
		echo $visitorIP;
		echo $name;
		echo $email';
		echo $datum;
		echo $message;
mysql_query("INSERT INTO cakula (ime, e_mail, poruka, datum, ip) VALUES ('$name','$email','$message','$datum', '$visitorIP')");
}
else
{
echo '<div class="notification_error">'.$error.'</div>';
}

}
?>

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Ok,

 

1)  He's saying the script you posted contains fatal PHP errors and will not execute or even parse.  The script you posted cannot possibly be echoing and sending emails, because it will not run in the form you gave us.

 

2)  You run an insert statement without running your arguments through mysql_real_escape_string.

 

3)  You have a query you believe is failing and you're not echoing (a) the query, or (b) the results of mysql_error(). 

 

Learn to help yourself and you'll be a much better programmer.  You have 2 error checking steps you have not performed.

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