multiple if() in one statement

[meltingpoint]

This works:

if($ABC == 'Yes' and $X != $Y){
echo "Error";
exit();
}

 

I need to evaluate one more set of variables in this statement like so;

 

This does not work:

if($ABC == 'Yes' and $X != $Y or $Z != $Y){
echo "Error";
exit();
}

 

So basically I need to echo an error if $ABC == Yes and both $X and $Z do not equal $Y

 

If gives an error because it is obviously not correct.  I do not know how to make it correct.  Any suggestions?

[darkfreaks]

//fixed with || which will return both true and false and just not false
if($ABC == 'Yes' and $X != $Y || $Z != $Y){
echo "Error";
exit();
}

[Pikachu2000]

You had the logic you need written out already: $ABC == Yes and both $X and $Z do not equal $Y . . .

 

if( $ABC == 'Yes' && $X != $Y && $Z != $Y) {

 

Edit: fixed tags . . .

[meltingpoint]

Thanks-  stared too long at the problem.

 

Cheers-