How to add link replacement

[AndyPSV]

How to modify code:

 

function rplLnk($x,$style='') {
$x = ereg_replace('[-a-z0-9!#$%&\'*+/=?^_`{|}~]+@([.]?[a-zA-Z0-9_/-])*','<a href=\'mailto:\\0\' '.$style.'>\\0</a>',$x);
$x = ereg_replace("[[:alpha:]]+://[^<>[:space:]]+[[:alnum:]/]", "<a href='\\0\' $style>\\0</a>", $x);
return $x;
}

 

to replace also "www.*.domain" as links

 

www.link.com

 

thank you

[AndyPSV]

. (mistake)

[ragax]

Hi Andy,

 

Since there are a million ways to match a url, here is a solution that uses the same way you have in your original code.

Just add this line before the return statement. It matches lines that have www dot, unless they are preceded by //, as those lines have already been turned into links by your earlier regex.

 

$x=preg_replace(',(?<!//)www\.[^<>[:space:]]+[[:alnum:]/],i','<a href="http://\0">\0</a>',$x);

 

This is only one in a thousand ways to do this. Please let me know if you need more help with it.

 

[AndyPSV]

Thank you, works perfectly.

[ragax]

Fantastic, glad to hear it.