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i have a file called filename.txt with the csv as below

 

Date,cet,predict,16d

Wed 02/15 @ 12Z,0.7,3.4,x

Wed 02/15 @ 18Z,0.7,3.3,x

Thu 02/16 @ 00Z,0.7,3.3,x

Thu 02/16 @ 06Z,1.1,3.7,x

Thu 02/16 @ 12Z,1.1,3.7,x

 

i would like the date to be replaced by numbers 1,2,3... and to be an array, and also the 2nd value in each row to be an array.

 

the number of rows is not fixed and grows day by day.

 

so the result would be (1,2,3,4,5) and (0.7,0.7,0.7,1.1,1.1).

 

can someone please help?

 

i guessed that some sort of loop is needed to go through row by row, adding values to an array.

 

I have tried the following with no success:

 

// get data from the file
$data = file_get_contents('filename.txt'); 

// use the newline as a delimiter to get different rows
$rows = explode("\n", $data); 
// go through all the rows starting at the second row
// remember that the first row contains the headings
for($i = 1; $i < count($rows); $i++){	
$temp = explode(',', $rows[$i]);	
$date = $temp[0];	
$cet = $temp[1];
$stack = array($stack);
array_push($stack, $cet);}
print_r ($stack);

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From what you have described.. I have no idea what you want to do.

 

But, I can tell you that instead of a loop for all this, you can use str_getcsv

// get data from the file
$data = file_get_contents('filename.txt'); 
$csv_data = str_csv($data);
// Now $csv_data is an array of it all.

 

sorted , if anyone is interested

 

// get data from the file
$aEntries = file('filename.txt',FILE_IGNORE_NEW_LINES);

// In case you want to keep the header for whatever
$sHeader = array_shift($aEntries);
$iCnt = count($aEntries);
for ($i = 0; $i < $iCnt; ++$i)
{
    $aParts = explode(',', $aEntries[$i]);
    $aResult[$i + 1] = $aParts[1];
}  

$aDates = array_keys($aResult);
$aCet = array_values($aResult);

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