function with css code for active button

[newphpcoder]

Hi..

 

I don't know if my idea is possible and if how can I do that.

 

I have functions for button onclick.

 

I have 3 buttons and I want to change the color of my button if it is active

 

here is my code

<script type="text/javascript">
//=========display parameter settings==========//
function display_PS(){
    document.loading_kanban.action="ParameterSettings.php";
    document.loading_kanban.submit();
}
//=======display kanban=========//
function display_Kanban(){
    document.loading_kanban.action="kanban_report.php";
    document.loading_kanban.submit();
}
//=========display SR==========//
function display_SR){
    document.loading_kanban.action="StockRequisition.php";
    document.loading_kanban.submit();
}
</script>
<div id="main_button">
<input type="button" name="parameter_settings" value="Parameter Settings" onclick="display_PS()">
<input type="button" name="parameter_settings" value="Stock Requisition" onclick="display_SR()"> 
<input type="button" name="parameter_settings" value="Kanban Report" onclick="display_Kanban()">
</div>

 

Is it possible to add code in my function for css active button..If no what should I do to change the color of my button for the client to know what page she is.

 

Thank you

[Adam]

Can you define 'active' please?