(SOLVED)Why wont this work ,help please

[just me and php]

This displays all tables and fields nicely , if i check box and click the delete button it acts like everything is ok no errors and it refreshes back to its own page but nothing was deleted , can someone see why??
Thanks :)
[code]
<?php
require "configdelete.php";
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);

$count=mysql_num_rows($result);

?>
<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td><form name="form1" method="post" action="">
<table width="400" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td bgcolor="#FFFFFF">&nbsp;</td>
<td colspan="4" bgcolor="#FFFFFF"><strong>Delete multiple rows in mysql</strong> </td>
</tr>
<tr>
<td align="center" bgcolor="#FFFFFF">#</td>
<td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td>

</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr><td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['id']; ?>"></td>
<td bgcolor="#FFFFFF"><? echo $rows['recno']; ?></td>
</tr>
<?php
}
?>
<tr>
<td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td>
</tr>
<?
// Check if delete button active, start this
if($delete){
for($i=0;$i<$count;$i++){
$del_id = $checkbox[$i];
$sql = "DELETE FROM $tbl_name WHERE id='$del_id'";
$result = mysql_query($sql);
}

// if successful redirect to delete_multiple.php
if($result){
echo "<meta http-equiv=\"refresh\" content=\"0;URL=delete_multiple.php\">";
}
}
mysql_close();
?>
</table>
</form>
</td>
</tr>
</table>
[/code]

[trq]

Where do you define $delete? You dont. You need to use the $_POST array. eg;

[code=php:0]
if ($_POST['delete']){
[/code]

[just me and php]

Thanks for the quick Reply
would i replace if($delete){
With if ($_POST['delete']){
?

i just try that and i have the same results

[trq]

Yes.

[just me and php]

Hmm that didnt change anything , had same results but?

should this
[code]$sql = "DELETE FROM $tbl_name WHERE id='$del_id'";[/code]

Be this?
[code] $sql = "DELETE recno, Username, track, HL_F, HL_MS, online, disp, PCLabel, PCValid, PC, date, display, hacked, MP, osFROM $tbl_name WHERE id='$del_id'";[/code]

With the
replace  if($delete){

With    if ($_POST['delete']){

[trq]

I think your logic is a little off. Should be something like...

[code=php:0]
if($_POST['delete']){
    foreach($_POST['checkbox'] as $del_id){
        $sql = "DELETE FROM $tbl_name WHERE id='$del_id'";
        if (mysql_query($sql))
            echo "Deleted $del_id";
        }
    }
}
[/code]

[just me and php]

Would  or can MYSQL be blocking me?

[just me and php]

can anyone give me an idea where im going wrong here?

[btherl]

Does it say "Deleted X", where X is a $del_id?

If not, there are 3 ways it could fail.  Either the query failed, $_POST['checkbox'] is empty or $_POST['delete'] is not true.

Try this:

[code]var_dump($_POST['delete']);
var_dump($_POST['checkbox']);[/code]

just before the if ($_POST['delete']);

Also, add an "else" case to the check for query failure:

[code]... } else {
  echo "Query $sql failed! Error was " . mysql_error();
}[/code]

[just me and php]

Thanks Guys Found the Problem I Wasnt Defining id So Code Couldnt Find It.
Thanks For The Help , And Thanks For This Forum ;)