How do I make this work?

[Rabastan]

I am using this line of code my site

 

<?php echo (IMAGES_HEADER . "header_02.jpg" ?>

 

I have a page defining all my directories, on that page I have this

 

 define('IMAGES_HEADER', DIR_IMAGES . 'header/');

 

instead of showing the image, all I am getting is "IMAGES_HEADERheader_02.jpg" where the image should be.

 

I am very new to PHP and trying to learn it, what in the world am I doing wrong??

 

Rab

 

[Mahngiel]

This:

<?php echo (IMAGES_HEADER . "header_02.jpg"; ?>

[Rabastan]

Thank You for your reply, I think I edited the code the way you explained,

 

I know have this....

 

<?php echo IMAGES_HEADER . "header_02.jpg"; ?>

 

However I am getting the same result 

 

Rab

[Rabastan]

Got it to work, it seems I failed to load the file that defined "IMAGE_HEADER"

 

Thanx

Rab

[Rabastan]

Now it seems I have a new problem using this code.....

 

<?php echo IMAGES_HEADER . "header_02.jpg"; ?>

 

Instead of displaying the actual image on my site I am getting the path of the image. It is displaying "images/header/header_02.jpg" instead.

 

Thank You in advance

[Mahngiel]

You still need to use valid HTML markup in order to call an image.  PHP will only create what you tell it to, and in the case of your code, it's: images/header/header_02.jpg

 

So put that information inside of an <img />

[Rabastan]

Again THANK YOU SO MUCH.

 

My last question is how to turn that into a link?

[Mahngiel]

http://www.tizag.com/htmlT/

[Rabastan]

I know how to do it in HTML, I am trying to learn php and there for try to use as php as possible in this site, not just wrap php in html.

 

Rab

[smerny]

php outputs html

[Psycho]

I know how to do it in HTML, I am trying to learn php and there for try to use as php as possible in this site, not just wrap php in html.

 

Your issue IS an HTML issue, not a PHP issue. If you know what the HTML markup should be then just use the PHP code to produce that markup. It doesn't happen automagically.

 

To output an image link in HTML

<a href="page_to_load.php"><img src="path/to/image.image.jpg"></a>

 

So, to do the same thing in PHP you can hard code the same thing or create variables for parts of the output

$href_url = "page_to_load.php";
$image_src = IMAGES_HEADER . "header_02.jpg";;
echo "<a href='{$href_url}'><img src='{$image_src}'></a>";