Make Birth Year Sticky

[doubledee]

I have PHP code that generates a long list of Birth Years in a Drop-down list, and I want to make the control "sticky".

 

I know how to make something like this sticky - thanks to help from you guys...

<!-- Gender -->
<label for="gender">Gender:</label>
<select id="gender" name="gender">
	<option value="">--</option>
	<option value="F"<?php echo (isset($gender) && $gender == "F") ? 'selected="selected"' : ''; ?>>Female</option>
	<option value="M"<?php echo (isset($gender) && $gender == "M") ? 'selected="selected"' : ''; ?>>Male</option>
</select>

 

 

But my Birth Year code is a little more complex and I'm racking me brain how to do it...

<!-- Birth Year -->
<label for="birthYear">Year Born:</label>
<select id="birthYear" name="birthYear">
	<option value="">--</option>
	<?php
		// Display dates for Users between 18 and 100.
		for($i = $newestYear; $i >= $oldestYear; $i--){
			echo '<option value="' . $i . '">' . $i . '</option>';
		}
	?>
</select>

 

How do I make this second set of code "sticky"?? 

 

Thanks,

 

 

Debbie

 

[spfoonnewb]

Something like this should work. You would replace 1980 with your set variable. Something like $dob, etc.

 

<!-- Birth Year -->
<label for="birthYear">Year Born:</label>
<select id="birthYear" name="birthYear">
    <option value="">--</option>
        <?php
        // Display dates for Users between 18 and 100.
        for($i = $newestYear; $i >= $oldestYear; $i--) {
            if ($i == 1980) {
                echo '<option value="' . $i . '" selected="selected">' . $i . '</option>';
            }
            else {
                echo '<option value="' . $i . '">' . $i . '</option>';
            }
        }
        ?>
</select>

[doubledee]

Something like this should work. You would replace 1980 with your set variable. Something like $dob, etc.

 

<!-- Birth Year -->
<label for="birthYear">Year Born:</label>
<select id="birthYear" name="birthYear">
    <option value="">--</option>
        <?php
        // Display dates for Users between 18 and 100.
        for($i = $newestYear; $i >= $oldestYear; $i--) {
            if ($i == 1980) {
                echo '<option value="' . $i . '" selected="selected">' . $i . '</option>';
            }
            else {
                echo '<option value="' . $i . '">' . $i . '</option>';
            }
        }
        ?>
</select>

 

I don't see how that code would work.

 

I need to make the Birth Year that the User selects "sticky".

 

You are arbitrarily making 1980 sticky, but it can't be static, it has to be based on what the User chose before submitting the form...

 

 

Debbie

 

[Muddy_Funster]

You would replace 1980 with your set variable. Something like $dob, etc.

so this isn't an option then?

[doubledee]

You would replace 1980 with your set variable. Something like $dob, etc.

so this isn't an option then?

 

I don't understand what he is telling me to do.

 

And I am saying that I need to maintain whatever value the User selects for his/her "Birth Year" in the drop-down.

 

I'm playing around with my code but not getting anywhere...

 

 

Debbie

 

 

[Psycho]

You would replace 1980 with your set variable. Something like $dob, etc.

[doubledee]

You would replace 1980 with your set variable. Something like $dob, etc.

 

That code won't work properly.

 

 

Debbie

 

[Muddy_Funster]

ok, so what condition are you using to atempt to define the condition of which year will be "sticky" then?

[doubledee]

This code does seem to work...

<!-- Birth Year -->
<label for="birthYear">Year Born:</label>
<select id="birthYear" name="birthYear">
	<option value="">--</option>
	<?php
		// Display dates for Users between 18 and 100.
		for($i = $newestYear; $i >= $oldestYear; $i--){
			if (isset($birthYear) && $birthYear == $i){
				echo '<option value="' . $i . '" selected="selected">' . $i . '</option>';
			}else{
				echo '<option value="' . $i . '">' . $i . '</option>';
			}
		}
	?>
</select>

 

 

Debbie

 

[Muddy_Funster]

which minus the isset part (which is a check you didn't mention anything about in the OP) is so very close to the code provided by spfoonnewb...

[Psycho]

for($year = $newestYear; $year >= $oldestYear; $year--)
{
    $selected = (isset($birthYear) && $birthYear == $year) ? ' selected="selected"' : '';
    echo "<option value='{$year}'{$selected}>{$year}</option>\n";
}

[doubledee]

WHy doesn't my code create new line breaks when I choose "View Source"...

if (isset($birthYear) && $birthYear == $year){
	echo '<option value="' . $year . '" selected="selected">' . $year . '</option>\n';
}else{
	echo '<option value="' . $year . '">' . $year . '</option>\n';
}

 

 

Debbie

 

[Psycho]

WHy doesn't my code create new line breaks when I choose "View Source"...

if (isset($birthYear) && $birthYear == $year){
	echo '<option value="' . $year . '" selected="selected">' . $year . '</option>\n';
}else{
	echo '<option value="' . $year . '">' . $year . '</option>\n';
}

 

http://php.net/manual/en/language.types.string.php

    Note: Unlike the double-quoted and heredoc syntaxes, variables and escape sequences for special characters will not be expanded when they occur in single quoted strings.

[doubledee]

http://php.net/manual/en/language.types.string.php

    Note: Unlike the double-quoted and heredoc syntaxes, variables and escape sequences for special characters will not be expanded when they occur in single quoted strings.

 

Can I just flip my single and double quotes?

 

And do I really even need to worry about newline breaks anyways?

 

 

Debbie

 

 

[Psycho]

for($year = $newestYear; $year >= $oldestYear; $year--)
{
    $selected = (isset($birthYear) && $birthYear == $year) ? ' selected="selected"' : '';
    echo "<option value='{$year}'{$selected}>{$year}</option>\n";
}

[doubledee]

for($year = $newestYear; $year >= $oldestYear; $year--)
{
    $selected = (isset($birthYear) && $birthYear == $year) ? ' selected="selected"' : '';
    echo "<option value='{$year}'{$selected}>{$year}</option>\n";
}

 

Okay, that works.

 

Thanks!!

 

BTW, what do your curly braces mean??

 

What are they doing??

 

 

Debbie

 

[Psycho]

BTW, what do your curly braces mean??

 

What are they doing??

 

http://www.php.net/manual/en/language.types.string.php#language.types.string.parsing

[doubledee]

BTW, what do your curly braces mean??

 

What are they doing??

 

http://www.php.net/manual/en/language.types.string.php#language.types.string.parsing

 

Okay, thanks again!

 

 

Debbie