dflow Posted April 16, 2012 Share Posted April 16, 2012 im trying to post var the_data2 as well <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="ro"> <head> <meta http-equiv="content-type" content="text/html; charset=iso-8859-2" /> <title>Example Ajax POST</title> <script type="text/javascript"><!-- // create the XMLHttpRequest object, according browser function get_XmlHttp() { // create the variable that will contain the instance of the XMLHttpRequest object (initially with null value) var xmlHttp = null; if(window.XMLHttpRequest) { // for Forefox, IE7+, Opera, Safari, ... xmlHttp = new XMLHttpRequest(); } else if(window.ActiveXObject) { // for Internet Explorer 5 or 6 xmlHttp = new ActiveXObject("Microsoft.XMLHTTP"); } return xmlHttp; } // sends data to a php file, via POST, and displays the received answer function ajaxrequest(php_file, tagID) { var request = get_XmlHttp(); // call the function for the XMLHttpRequest instance // create pairs index=value with data that must be sent to server var the_data = 'page_id='+document.getElementById('txt2').innerHTML; var the_data2 = 'page_id2='+document.getElementById('txt22').innerHTML; request.open("POST", php_file, true); // set the request // adds a header to tell the PHP script to recognize the data as is sent via POST request.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); request.send(the_data,the_data2); // calls the send() method with datas as parameter // Check request status // If the response is received completely, will be transferred to the HTML tag with tagID request.onreadystatechange = function() { if (request.readyState == 4) { document.getElementById(tagID).innerHTML = request.responseText; } } } --></script> </head> <body> <h5 style="cursor:pointer;" onclick="ajaxrequest('process-addpage.php', 'context')"><u>Click</u></h5> <div id="txt2" style="display:none;"><?php echo $page_id=33333;?></div> <div id="txt22" style="display:none;"><?php echo $page_id2=55555;?></div> <div id="context">Here will be displayed the response from the php script.</div> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/261039-syntax-help-add-vars-to-requestsend/ Share on other sites More sharing options...
kicken Posted April 16, 2012 Share Posted April 16, 2012 You need to build what looks like a query string and pass that to .send() eg: // create pairs index=value with data that must be sent to server var the_data = 'page_id='+encodeURIComponent(document.getElementById('txt2').innerHTML); var the_data2 = 'page_id2='+encodeURIComponent(document.getElementById('txt22').innerHTML); var post_data = the_data + '&' + the_data2; //..rest of code request.send(post_data); Quote Link to comment https://forums.phpfreaks.com/topic/261039-syntax-help-add-vars-to-requestsend/#findComment-1337846 Share on other sites More sharing options...
dflow Posted April 16, 2012 Author Share Posted April 16, 2012 You need to build what looks like a query string and pass that to .send() eg: // create pairs index=value with data that must be sent to server var the_data = 'page_id='+encodeURIComponent(document.getElementById('txt2').innerHTML); var the_data2 = 'page_id2='+encodeURIComponent(document.getElementById('txt22').innerHTML); var post_data = the_data + '&' + the_data2; //..rest of code request.send(post_data); kool thanks Quote Link to comment https://forums.phpfreaks.com/topic/261039-syntax-help-add-vars-to-requestsend/#findComment-1337876 Share on other sites More sharing options...
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