break out of echo for an if statement

[fife]

Can someone please help with this if statement.  Im having trouble breaking out of the echo

 

do {
		  echo" <table width='150' border='0'>
	 <tr><td align='left' valign='top'>
	<a href='edit-page.php?page={$page['pageid']}'", if($page['status']==0){echo "class='inactive'"} ">{$page['pagename']}</a>
	</td></tr>
	</table>";

		 }while ($page = mysql_fetch_assoc($pagesq)); 

 

Getting told by my software I have an syntax error.

[PravinS]

Try this code

do 
{
	$class = '';
	if ($page['status'] == 0)
		$class = 'class="inactive"';
	echo '<table width="150" border="0">
			<tr><td align="left" valign="top">
			<a href="edit-page.php?page='.$page['pageid'].'" '.$class.'>'.$page['pagename'].'</a>
			</td></tr>
			</table>';
}
while ($page = mysql_fetch_assoc($pagesq)); 

[cyberRobot]

You could also have multiple echo statements:

 

<?php
do {
echo " <table width='150' border='0'>
<tr><td align='left' valign='top'>
<a href='edit-page.php?page={$page['pageid']}'";
if($page['status']==0){ echo "class='inactive'"; }
echo ">{$page['pagename']}</a>
</td></tr>
</table>";

}while ($page = mysql_fetch_assoc($pagesq)); 
?>

[scootstah]

You can use a ternary operator:

<a href='edit-page.php?page={$page['pageid']}' " . ($page['status']==0 ? "class='inactive'" : "") . ">{$page['pagename']}</a>