Not showing the "else" info

[colleyboy]

I have an if statement:

 

// if they are logged in


$aretheyliked = mysql_query("SELECT * FROM boom_likes WHERE user_id=$loggedinuserid");

while($row = mysql_fetch_array($aretheyliked))
  {

if (($row['liked_user_id']==$profileuserid)&&($row['user_id']==$loggedinuserid)){
echo "<FONT SIZE=1 COLOR=BLUE>You Like This Artist";

}
else
{
echo "<FONT SIZE=2 COLOR=BLUE>Like";
}

 

The idea is if the user is logged in they can click the "like".  If they already like it it will say they already do like it.    The else is not showing though.  What am I doing wrong... it works when it matches but not when it dont

[scootstah]

I don't see anything syntactically wrong. Is it showing up in the page source? Maybe you have malformed HTML somewhere (speaking of which, you need to close those two font tags (actually you should really be using CSS instead of font tags, but I digress)).

 

Also, this &&($row['user_id']==$loggedinuserid) is unnecessary since you are only selecting rows with that user id to start with.

[colleyboy]

Hello,

 

I have gave you an extended snippet of the code and removed the && as I see I reference it twice (good spot ).

 

The <FONT> tags are temp until I sort the code then I will cleanup with some CSS .

 

<!-- LIKE BUTTON -->


<?php

if (isset($_SESSION['useridkey'])){

//check user id in url matches useridkey

if ($_SESSION['useridkey']==$the_user_id){

// the following if the session id matches the variable

//edit profile page

echo "sessionid matches the user id variable";

}

$loggedinuserid = $_SESSION['useridkey'];

// if they are logged in


$aretheyliked = mysql_query("SELECT * FROM boom_likes WHERE user_id=$loggedinuserid");

while($row = mysql_fetch_array($aretheyliked))
  {

//if they are liked by the user

if (($row['liked_user_id']==$profileuserid))){

echo "<FONT SIZE=1 COLOR=BLUE>You Like This Artist";

}
else
{
echo "Like";
}



}




// end of if they are logged in

}
else
{

// if they are not logged in

echo "<FONT SIZE=1 COLOR=RED>You must be logged in to like this artist";

}

?>


<!-- END OF LIKE BUTTON -->

[colleyboy]

Tried an elseif statement too (!=) but still isnt showing the echo... hmm

[Pikachu2000]

Is it showing up in the page source?

[colleyboy]

No it is blank on the page source where it should say "like"

[Pikachu2000]

Are you sure the last code you posted is the code you're actually running? That code throws a fatal parse error when I run it.

 

EDIT: And do you have error reporting set up to display all errors?