rrayner Posted July 6, 2012 Share Posted July 6, 2012 I have this bit of code which should do an alert popup which did work until i tried to put a line feed into it what am I doing wrong if ($linecount > 24) { echo "<script type=\"text/javascript\">alert('Hello\n How are you?')</script>"; } ?> Thanks Quote Link to comment https://forums.phpfreaks.com/topic/265320-popup-help/ Share on other sites More sharing options...
Adam Posted July 6, 2012 Share Posted July 6, 2012 You're echoing the line-feed in PHP, not JS. That means: alert('Hello How are you?') ... Is the JS being sent to the browser, which is invalid syntax. Strings can't span over multiple lines without a backslash at the end of the previous line. In PHP you can send the literal string "\n" by escaping it with a backslash (so a double backslash really): echo "<script type=\"text/javascript\">alert('Hello\\n How are you?')</script>"; Or by using single quotes, because special characters aren't parsed in single quote strings: echo '<script type="text/javascript">alert("Hello\n How are you?")</script>'; Although there's no need at all to use PHP to echo the string, you could just close the PHP tag and re-open it after: { ?> <script type="text/javascript">alert('Hello\n How are you?')</script> <?php } Quote Link to comment https://forums.phpfreaks.com/topic/265320-popup-help/#findComment-1359691 Share on other sites More sharing options...
rrayner Posted July 6, 2012 Author Share Posted July 6, 2012 Thanks for your help got it working the \\n Thanks again. Quote Link to comment https://forums.phpfreaks.com/topic/265320-popup-help/#findComment-1359694 Share on other sites More sharing options...
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