Unexpected Variable - Radio Buttons

[iseriouslyneedhelp]

I've tried this every which way that I can think of and I keep getting an error for unexpected variable. I know it has to do with the single quotes around 'Yes' and 'No' but I can't figure out how else to make this work, can anyone help me with the code. Thanks!

 

It's suppose to show Yes or No based on what's in my table (contacts) for the column subscribesearches.

 

<?php

function subscribe ($conn) {

$ID = $_GET['ID'];

    $stmt = $conn->prepare("SELECT ID,subscribesearches,subscribedrips FROM contacts WHERE ID = '$ID'");
	$stmt->execute();
	$stmt->bind_result($ID,$subscribesearches,$subscribedrips);
	$stmt->fetch();  

	echo'
	<td>
	<input type="radio" name="subscribesearches" value="Yes" $subscribesearches == 'Yes' ?  "checked" : "" ><span class="r-input">  Yes</span>
	<input type="radio" name="subscribesearches" value="No" $subscribesearches == 'No' ? "checked" : "" ><span class="r-input">  No</span>
	</td>';

$stmt->close();

}
?>

[kicken]

You have to break out of your string to do your condition, and use concatenation to join them.

 

	echo'
	<td>
	<input type="radio" name="subscribesearches" value="Yes" '.($subscribesearches == 'Yes' ?  "checked" : "").' ><span class="r-input">  Yes</span>
	<input type="radio" name="subscribesearches" value="No" '.($subscribesearches == 'No' ? "checked" : "").' ><span class="r-input">  No</span>
	</td>';

 

[iseriouslyneedhelp]

You have to break out of your string to do your condition, and use concatenation to join them.

 

	echo'
	<td>
	<input type="radio" name="subscribesearches" value="Yes" '.($subscribesearches == 'Yes' ?  "checked" : "").' ><span class="r-input">  Yes</span>
	<input type="radio" name="subscribesearches" value="No" '.($subscribesearches == 'No' ? "checked" : "").' ><span class="r-input">  No</span>
	</td>';

 

Awesome, I tried something close to that, but obviously not close enough! Thanks for explaining!