How to display data from a mysql table in rows of 4?

[Stalingrad]

Hi! This is probably simple, and I know it is, I just need my memory refreshed at this point. I will show you the data I want to grab in a minute. I want to display the data like this:

 

NAME    NAME    NAME  NAME

IMAGE  IMAGE  IMAGE  IMAGE

 

 

NAME  NAME  NAME  NAME

IMAGE  IMAGE  IMAGE IMAGE

 

etc...(it will ocntinue on with whatever is in the table, and stop when the data stops).

 

I know there will be a simple table involved in this too.

 

Here is the table information and query:

 

 

$infoq = "SELECT * FROM items WHERE itemid='$umiid'";
$info = mysql_query($infoq);
while($row = mysql_fetch_array($info)) {
$myname = $row['name'];
$myid = $row['itemid'];
$myimage = $row['image'];
$mydesc = $ow['description'];
$myrarity = $row['rarity'];

echo "$myname<br><img src=/images/items/$myimage>";
}

 

I am wanting to display the "myname" as the name, and the "my image" as the image, underneath the name.

 

Thank you for your help in advance!

[Barand]

try reading this other current thread

 

http://forums.phpfreaks.com/index.php?topic=363103.0

[jazzman1]

@off, nice nick dude 

[scootstah]

Something like...

$i = 1;

while($row = mysql_fetch_array($info)) {
$myname = $row['name'];
$myid = $row['itemid'];
$myimage = $row['image'];
$mydesc = $ow['description'];
$myrarity = $row['rarity'];

echo "<div style=\"float:left;\">$myname<br><img src=/images/items/$myimage></div>";

if ($i % 4 == 0) {
	echo '<br style="clear:both;" />';
}

$i++;
}