jazzman1

I did it. You had to tell me about that So, there is no way to login using curl to this page, at least I don't know how to do this task. Sorry....maybe somebody would help you here I will try later on.

You are still continue to teach me how the server and client works. No problem, no offense is taken by me Now, I already know that there is not way php to detect if javascript is enabled / disabled in my browser when I make an ajax call to the server. So, back to the OP problem, here is the logic credentials: #!/bin/bash NAME='user' PASS='pass' referer='http%3a%2f%2fwww.bet365.com%2fxtra%2fen%2f' #curl --cookie-jar cjar --output /dev/null 'https://members.bet365.com/Members/lp/default.aspx' curl --cookie cjar --cookie-jar cjar 'https://members.bet365.com/Members/lp/default.aspx' --data "

Ok, do it for me and send me the login credentials.

Jacques, who is talking about how the server treats the http post/get form? I am talking about that there is no way to make an ajax call without javascript and this could be easily checked (if js is enabled/disabled by php ( php is cross-side language)) CroNiX in the official docs of cURL, there is nothing about js and curl implementation. I don't think your example is possible to send data in this way by curl. muppet77, what is your username and password. Send me a PM if you want it, to check if it's possible to use curl and lately I'll post the solution to the forum.

Ok, how will you send an ajax request (if the script is required) without javascript?

This login page requires javascript to be enabled in your browser. No way to use cURL.

In the process_applicants.php file you also need to call start_secure_session() before using login_check(), otherwise you will get a notice of undefined variables, only the start_secure_session() function contains session_start() itself in your script. Even the both function are in the same file, any variable used inside a function is by default limited to the local function scope. Also, when using a php header function you need to call an exit command at the end. header('Location:http://main_function_page.htm'); exit;

Before looking the script into the login_check function, check first, if your login is being successful (or not) inside the login function and the both $_SESSION['user_name'] and $_SESSION['login_string'] variables are being defined. function login($user_name, $password, $mysqli) { // Using prepared statements means that SQL injection is not possible. if ($stmt = $mysqli->prepare("SELECT user_name, password, salt FROM user_profiles WHERE user_name = ? ")) { $stmt->bind_param('s', $user_name); // Bind "$user_name" to parameter. $stmt

Any errors?

Double check the script of this file and make sure that this constant is difened! <?php /** * These are the database login details */ define("HOST", "localhost"); // The host you want to connect to. define("USER", "sec_user"); // The database username. define("PASSWORD", "4Fa98xkHVd2XmnfK"); // The database password. define("DATABASE", "secure_login"); // The database name. define("CAN_REGISTER", "any"); define("DEFAULT_ROLE", "member"); define("SECURE", FALSE); // FOR DEVELOPMENT ONLY!!!!

You shoud get some error messages without them I am affraid we cannot help you.Try to add the following error_reporting functions on the top of the file you call. ini_set('display_startup_errors',1); ini_set('display_errors',1); error_reporting(-1);

You should get an error message if you're trying to post a huge script. If so, you need to post only that piece(s) of code that relevant to your actual problem.

Post all relevant code here using forum's code tags and don't attach files when providing code, some users like me do not like the idea to download files into their own macines.

Yep, david is right, since you have a ssh access to this account, login into your terminal and try to call sendmail directly from the shell. Try, again to send me an email with a message od current date/time. The command is: echo `date` | /usr/sbin/sendmail tuparov86@gmail.com // or echo `date` | sendmail tuparov86@gmail.com

yes...that's just fine....so I don't see anything wrong and I don't have any idea why you're running into a false result. Try those two solutions if they don't work maybe someone else would help you on this. 1. <?php $email_to = 'tuparov86@gmail.com'; $email_from = $_SERVER['HTTP_HOST']; $email_subject = 'Mail subject'; $email_message = 'Mail message......'; // create email headers $headers = 'MIME-Version: 1.0' . "\r\n"; $headers .= 'Content-type: text/plain; charset=iso-8859-1' . "\r\n"; $headers .= "From: <$email_from>\r\n"; $headers .= "Reply-To: <$email_from>