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This is a part of my Mysql query and getting the values from the rows wheres tasks.owner.id = logged in user so it only shows the tasks assigned to the logged in user.

 

This is a task manager script i?m trying to make, so i want it to echo out who made this task by name, and the ID of the user that made it is stored in $made_id in table "tasks" and i need this to get the name (row) with the same id in the "users" table.

 

How could i do this?

 

As i see it, the query already contains booth the ID and the Name of the users, but i need to put theese to together in some way.

 

$query = mysql_query("SELECT * FROM tasks JOIN login_users WHERE tasks.owner_id = '$user' GROUP BY tasks.id ");

if ( mysql_num_rows( $query ) > 0 )
{

while ($row = mysql_fetch_array($query)){

$id = $row['id'];
$title = $row['title'];
$details = $row['details'];
$yourref = $row['yourref'];
$made_id = $row['made_id'];
$made_date = $row['made_date'];
$due_date = $row['due_date'];
$name = $row['name'];


?>

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https://forums.phpfreaks.com/topic/266332-get-name-by-id-from-other-table/
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Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in /Applications/XAMPP/xamppfiles/htdocs/home.php on line 36

 

$query = mysql_query("SELECT *, b.name FROM tasks AS a LEFT JOIN login_users AS b ON a.owner_id=b.id WHERE a.owner_id = '$user' GROUP BY a.id");

 

 

The table names are correct.

 

Should it be:

 

ON a.made_id=b.id

 

Since it`s the made_id that i?m trying to link up with the id on the users table?

 

But this query failed as well..

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