str0kes Posted July 29, 2012 Share Posted July 29, 2012 Hello guys, I have problem with the script i was coding. This is a simple news script. I am not able to add information to the database. I don't know what Im doing wrong. Here is my php code: <?php if (isset($_POST['submit'])) { $title=$_POST['title']; $small_text =$_POST['small_text']; $full_text=$_POST['full_text']; include("connectmysql.php"); mysql_query("insert into main (id,title,small_text,full_text) values('$id','$title','$small_text','$full_text')"); } ?> here is html: <FORM name="forma2" action="?" method="post" enctype="multipart/form-data"> <TABLE> <TR> <TD>Title</TD> <TD> <input type="text" size="70" name="title"> </TD> </TR> <TR> <TD>small text</TD> <TD> <input type="text" size="80" name="small_text"> </TD> </TR> <TR> <TD>full text</TD> <TD> <textarea cols="60" rows="12" name="full_text"></textarea> </TD> </TR> <TR> <TD>picture</TD> <TD><input type="file" name="picture"></TD> </TR> <TR> <TD>picture</TD> <TD><input type="file" name="picture2"></TD> </TR> <TR> <TD>picture</TD> <TD><input type="file" name="picture3"></TD> </TR> <TR> <TD>picture</TD> <TD><input type="file" name="picture4"></TD> </TR> <TR> <TD>picture</TD> <TD><input type="file" name="picture5"></TD> </TR> <TR> <TD>picture</TD> <TD><input type="file" name="picture6"></TD> </TR> <TR> <TD></TD> <TD><input type="submit" value="submit"></TD> </TR> </TABLE> </form> I tried to use $id=Time("U"); and then i used $id=$_POST[id] but didn't get it working. Any help please? Thanks in advance Link to comment https://forums.phpfreaks.com/topic/266406-problems-with-database/ Share on other sites More sharing options...
jazzman1 Posted July 30, 2012 Share Posted July 30, 2012 I don't see input element with name - submit. Link to comment https://forums.phpfreaks.com/topic/266406-problems-with-database/#findComment-1365320 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.