Need help echoing values

[XCVIII]

I have created a form that outputs information to my mysql data.

 

For example if I enter a value in a text field the value gets sent to the database and is stored as $example="value"

 

There is a populated list and its set up like this:

 

<?php

$example1="value1";

$example2="value2";

$example3="value3";

$example4="value4";

$example5="value5";

$example6="value6";

?>

 

So far everything is working, I am able to store information in the database.

 

However when I try to echo the information in my page it doesn't come up at all, its blank.

 

I can however echo the whole table but then it comes up like this:

 

<?php

$example1="value1";

$example2="value2";

$example3="value3";

$example4="value4";

$example5="value5";

$example6="value6";

?>

 

I need to echo the values separately in a text, e.g.

 

This is an example $example1 and this is what $example2 I need,

I need to echo $example3 the values individually $example 4 etc $example5

 

 

I don't know what I'm doing wrong, echoing the whole table works with:

 

$zeile=mysql_fetch_array($ger);

echo("\n".$seile['code']."\n");

 

But id like to do it separately.

[Christian F.]

I think you should start with the PHP manual tutorial. Then read up on PHP arrays and "mysql_fetch_array ()".

 

PS: Do note that the mysql_* () functions are deprecated, and that you should use MySQLi or PDO instead. (Read more about them in the manual.)

[vinsux]

Like this??

 

$check = mysql_query("SELECT * FROM YourtableName")or die(mysql_error());

	while($info = mysql_fetch_array( $check )) 	
	{
         $example1="value1";
        $example2="value2";
        $example3="value3";

       echo "$example1";
         }

[Christian F.]

There is no point in using single variables, use arrays instead. Will give you a lot less headaches working with the code.

Trust me.