boo_lolly Posted November 9, 2006 Share Posted November 9, 2006 error![b]Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/httpd/vhosts/hiphopjam4kidz.com/www/merchandise/includes/item_display.inc on line 27[/b]what does that mean?!?here's lines 20 - 35 of item_display.inc:[code=php:0] </font></b> </td> <? // Now lets see if we need to start a new row $tot = 0; $rtot = 0; $rows = $config[rows_display]; $cols = $config[cols_display]; while ($i = mysql_fetch_array($iQuery)) { //<---- LINE 27 if(($tot % $config[cols_display]) == 0) { print " </tr><tr>"; } // New row accomplished if needed print " <td align=center class=\"header\">\n"; print " <table border=0 width=\"100%\">"; print " <tr>"; print " <td class=\"header\" align=left width=\"200\">";[/code] Link to comment https://forums.phpfreaks.com/topic/26721-mysql-error-this-is-pissin-me-off/ Share on other sites More sharing options...
joshi_v Posted November 10, 2006 Share Posted November 10, 2006 what i could say is there must be an error in your query.Just print the query to browser and test it for errors in phpMyadmin or mysql prompt.Still you had a problem with the query post it here.any one can help you. Link to comment https://forums.phpfreaks.com/topic/26721-mysql-error-this-is-pissin-me-off/#findComment-122554 Share on other sites More sharing options...
AndyB Posted November 10, 2006 Share Posted November 10, 2006 Don't double post. Link to comment https://forums.phpfreaks.com/topic/26721-mysql-error-this-is-pissin-me-off/#findComment-122637 Share on other sites More sharing options...
Recommended Posts