boo_lolly Posted November 9, 2006 Share Posted November 9, 2006 error![b]Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/httpd/vhosts/hiphopjam4kidz.com/www/merchandise/includes/item_display.inc on line 27[/b]what does that mean?!?here's lines 20 - 35 of item_display.inc:[code=php:0] </font></b> </td> <? // Now lets see if we need to start a new row $tot = 0; $rtot = 0; $rows = $config[rows_display]; $cols = $config[cols_display]; while ($i = mysql_fetch_array($iQuery)) { //<---- LINE 27 if(($tot % $config[cols_display]) == 0) { print " </tr><tr>"; } // New row accomplished if needed print " <td align=center class=\"header\">\n"; print " <table border=0 width=\"100%\">"; print " <tr>"; print " <td class=\"header\" align=left width=\"200\">";[/code] Link to comment Share on other sites More sharing options...
joshi_v Posted November 10, 2006 Share Posted November 10, 2006 what i could say is there must be an error in your query.Just print the query to browser and test it for errors in phpMyadmin or mysql prompt.Still you had a problem with the query post it here.any one can help you. Link to comment Share on other sites More sharing options...
AndyB Posted November 10, 2006 Share Posted November 10, 2006 Don't double post. Link to comment Share on other sites More sharing options...
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