Preg_replace with quote exceptions

[jackr1909]

Hi,

 

I have a function that converts URL's in a string to links:

 

$return = preg_replace('@(https?://([-\w\.]+[-\w])+(:\d+)?(/([\w/_\.#-]*(\?\S+)?[^\.\s])?)?)@', '<a href="$1" target="_blank">$1</a>', $return);

 

Can i have some help amending it to exclude any links that are in quotes. Thanks

[jazzman1]

The easiest way is to use RegEx to exclude any links that are in quotes.

[jackr1909]

How would i apply that?

[Psycho]

Try putting a negated quote match just before the http"

$return = preg_replace('@[^"\'](https?://([-\w\.]+[-\w])+(:\d+)?(/([\w/_\.#-]*(\?\S+)?[^\.\s])?)?)@',
                       '<a href="$1" target="_blank">$1</a>',
                       $return);