wasssu Posted September 29, 2012 Share Posted September 29, 2012 Hi, I want to build a tree menu (table with categories on 3 level) from database. I want to look like this using unsorted lists (3 levels): Category1 -Subcategory 1 -Subcategory 2 -Sub-Subcategory 1 -Sub-Subcategory 1 Category2 -Subcategory 1 -Subcategory 2 -Subcategory 3 -Sub-Subcategory 1 -Sub-Subcategory 1 -Subcategory 4 The structure of the Category table is like this: category_id parent_id So i put from database into an array(): $menu = Array(); while ($m = mysql_fetch_array($result)) { $menu[] = Array('id'=>$m['category_id'], 'parent'=>$m['parent_id']); } But from here i've tried different algorithms but it does't work. I have only 2 main categories: category_id = 207 parent_is = 0 category_id = 286 parent_is = 0 And then sub categories and sub subcategories Could you please help me with this? Thank you!! Quote Link to comment https://forums.phpfreaks.com/topic/268903-tree-menu-from-database-3-levels-2-records-on-first-level/ Share on other sites More sharing options...
jcbones Posted September 29, 2012 Share Posted September 29, 2012 You need to line up the data, when it comes from the database, correctly. I would start with ordering it sorted by the parent ascending. Then I would sort that into an array, matching the id's to the parent. Finally, I would go through that array, and build the menu. Quote Link to comment https://forums.phpfreaks.com/topic/268903-tree-menu-from-database-3-levels-2-records-on-first-level/#findComment-1381728 Share on other sites More sharing options...
wasssu Posted September 29, 2012 Author Share Posted September 29, 2012 You need to line up the data, when it comes from the database, correctly. I would start with ordering it sorted by the parent ascending. Then I would sort that into an array, matching the id's to the parent. Finally, I would go through that array, and build the menu. I've found this but i don't know why is not working. It seems that i'm not building correctly the arrays. Whe i'm using the commented code for #menu is working: $result = mysql_query("SELECT * FROM category") or die(mysql_error()); while ($m = mysql_fetch_array($result)) { $menu1[] = Array('id'=>$m['category_id'], 'parent'=>$m['parent_id']); } $menu = Array($menu1); /*$menu = Array( // Presumed to have been coming from a SQL SELECT, populated for demo. Array('id'=>1,'title'=>'Menu 1', 'parent_id'=>null), Array('id'=>2,'title'=>'Sub 1.1', 'parent_id'=>1), Array('id'=>3,'title'=>'Sub 1.2', 'parent_id'=>1), Array('id'=>4,'title'=>'Sub 1.3', 'parent_id'=>1), Array('id'=>5,'title'=>'Menu 2', 'parent_id'=>null), Array('id'=>6,'title'=>'Sub 2.1', 'parent_id'=>5), Array('id'=>7,'title'=>'Sub Sub 2.1.1', 'parent_id'=>6), Array('id'=>8,'title'=>'Sub 2.2', 'parent_id'=>5), Array('id'=>9,'title'=>'Menu 3', 'parent_id'=>null), );*/ function has_children($rows,$id) { foreach ($rows as $row) { if ($row['parent_id'] == $id) return true; } return false; } function build_menu($rows,$parent=0) { $result = "<ul>"; foreach ($rows as $row) { if ($row['parent_id'] == $parent){ $result.= "<li>{$row[title]}"; if (has_children($rows,$row['id'])) $result.= build_menu($rows,$row['id']); $result.= "</li>"; } } $result.= "</ul>"; return $result; } echo build_menu($menu); ?> Quote Link to comment https://forums.phpfreaks.com/topic/268903-tree-menu-from-database-3-levels-2-records-on-first-level/#findComment-1381730 Share on other sites More sharing options...
Barand Posted September 29, 2012 Share Posted September 29, 2012 (edited) It's easier to build a 2D array with parent as the key. This should get you going. <?php include("testDBconnect.php"); $sql = "SELECT category_id, name, parent FROM category"; $res = $mysqli->query($sql); $cats = array(); while ($row = $res->fetch_assoc()) { extract ($row); $cats[$parent][] = array ('id'=>$category_id, 'name'=>$name); } listCats($cats, 0); // call recursive list function function listCats(&$cats, $parent, $level=0) { if (isset($cats[$parent])) foreach ($cats[$parent] as $subcat) { $indent = str_repeat('----', $level); echo "$indent{$subcat['name']}<br />"; listCats($cats, $subcat['id'], $level+1); } } ?> Edited September 29, 2012 by Barand Quote Link to comment https://forums.phpfreaks.com/topic/268903-tree-menu-from-database-3-levels-2-records-on-first-level/#findComment-1381731 Share on other sites More sharing options...
jazzman1 Posted September 29, 2012 Share Posted September 29, 2012 Check this out -> http://www.sitepoint.com/hierarchical-data-database/ Quote Link to comment https://forums.phpfreaks.com/topic/268903-tree-menu-from-database-3-levels-2-records-on-first-level/#findComment-1381733 Share on other sites More sharing options...
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