Parse error: syntax error, unexpected '>' in /home/vs/b/search.php on line 42

[Venkatesh]

<?php

  // Get the search variable from URL

  $var = @$_GET['q'] ;
  $trimmed = trim($var); //trim whitespace from the stored variable

// rows to return
$pagenum=10;

// check for an empty string and display a message.
if ($trimmed == "")
  {
  echo "<p>Please enter a search...</p>";
  exit;
  }

// check for a search parameter
if (!isset($var))
  {
  echo "<p>We dont seem to have a search parameter!</p>";
  exit;
  }

//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost","vasudhai_vss","vsspl"); //(host, username, password)

//specify database ** EDIT REQUIRED HERE **
mysql_select_db("vasudhai_Web") or die("Unable to select database"); //select which database

we're using

// Build SQL Query 
$query = "select * from Hyd_Contacts where Category like \"%$trimmed%\";

$numresults=mysql_query($query);
$numrows=@mysql_num_rows($numresults);

// If we have no results, offer a google search as an alternative

[b]if ($numrows == 0)[/b]  //line no 42
  {
  echo "<h4>Results</h4>";
  echo "<p>Sorry, your search: &quot;" . $trimmed . "&quot; returned zero results</p>";

// google
echo "<p><a href=\"http://www.google.com/search?q="
  . $trimmed . "\" target=\"_blank\" title=\"Look up
  " . $trimmed . " on Google\">Click here</a> to try the
  search on google</p>";
  }

// next determine if s has been passed to script, if not use 0
  if (empty($s)) {
  $s=0;
  }

// get results
  $query .= " pagenum $s,$pagenum";
  $result = mysql_query($query) or die("Couldn't execute query");

// display what the person searched for
echo "<p>You searched for: &quot;" . $var . "&quot;</p>";

// begin to show results set
echo "Results";
$count = 1 + $s ;

// now you can display the results returned
  while ($row= mysql_fetch_array($result)) {
  $title = $row["1st_field"];

  echo "$count.)&nbsp;$title" ;
  $count++ ;
  }

$currPage = (($s/$pagenum) + 1);

//break before paging
  echo "<br>";

  // next we need to do the links to other results
  if ($s>=1) { // bypass PREV link if s is 0
  $prevs=($s-$pagenum);
  print "&nbsp;<a href=\"$PHP_SELF?s=$prevs&q=$var\">&lt;&lt;
  Prev 10</a>&nbsp&nbsp;";
  }

// calculate number of pages needing links
  $pages=intval($numrows/$pagenum);

// $pages now contains int of pages needed unless there is a remainder from division

  if ($numrows%$pagenum) {
  // has remainder so add one page
  $pages++;
  }

// check to see if last page
  if (!((($s+$pagenum)/$pagenum)==$pages) && $pages!=1) {

  // not last page so give NEXT link
  $news=$s+$pagenum;

  echo "&nbsp;<a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 &gt;&gt;</a>";
  }

$a = $s + ($pagenum) ;
  if ($a > $numrows) { $a = $numrows ; }
  $b = $s + 1 ;
  echo "<p>Showing results $b to $a of $numrows</p>";
 
?>

Please try to check complete code, i am new to php & MySql

[haaglin]

In your query, add a doublequote at the end,
[code]$query = "select * from Hyd_Contacts where Category like \"%$trimmed%\"; [/code]

needs to be
[code]$query = "select * from Hyd_Contacts where Category like \"%$trimmed%\""; [/code]

[AndyB]

PLEASE do not post what is effectively the same (bad syntax) problem in a separate thread.