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Hi,

 

I have copied the following code from a book. It displays the image but I have no idea where the temporary file and permanent file is stored.

 

Any suggestions on how I can determine where the image is stored.

 

 

<?php // upload.php
echo <<<_END
<form method='post' action='upload.php' enctype='multipart/form-data'>
Select a JPG, GIF, PND or TIF File
<input type='file' name='filename' size='20' />
<input type='submit' value='Upload' />
</form>
_END;


if ($_FILES)
{
$name = $_FILES['filename']['name'];

switch($_FILES['filename']['type'])
{
case 'image/jpeg': $ext = 'jpg'; break;
case 'image/gif': $ext = 'gif'; break;
case 'image/png': $ext = 'png'; break;
case 'image/tiff': $ext = 'tif'; break;
default:   $ext = ''; break;
}
if ($ext)
{
$n = "image.$ext";
move_uploaded_file($_FILES['filename']['tmp_name'], $n);
echo "Upload image '$name' as '$n':<br />";
echo "<img src='$n' />";
}
else echo "'$name' is not accepted image file";
}
else echo "No image has been uploaded";
?>

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https://forums.phpfreaks.com/topic/269917-image-stored-location/
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Rather than number them 1, 2, 3, etc just generate a unique string.  Either using the current time value, or something like uniqid.  If you want to make sure the generated name doesn't exist, keep generating a new name in a loop so long as file_exists returns true.

Rather than number them 1, 2, 3, etc just generate a unique string. Either using the current time value, or something like uniqid. If you want to make sure the generated name doesn't exist, keep generating a new name in a loop so long as file_exists returns true.

 

Thats what I was looking for! Cheers dude. That sounds much better.

 

Then I take it all I need to do is to add the random number (123456.png) into a column under the members profile. Then I can echo just the number into the image tag from the database.

 

Cheers dude.

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