Jump to content

Remove Form Tags When Calling Renderpartial In Yii


teng84

Recommended Posts

see if you can use any of this code to try to do what you want.. i didnt understand to well

 

<style type="text/css">
span.About {
  background:url(images/ABOUT.png) top center no-repeat;    

   display:block;
   height:26px;
border:none;



}
span.AboutMore {
  background:url(images/ABOUT.png) top center no-repeat;    

   display:block;
   height:26px;
border:none;



}
</style>
<?
$checked = "checked";



if (!empty($_POST['newClient']))
{
echo '$checked'; 
?>
<input name="newClient" type="radio" id="id_radio1" value= "check1" checked="<? $checked ?>"  onclick="javascript:Function_Name();"/>  New Client
<?
}
else
{
?>
<input id="id_radio2" type="radio" value= "check2" name="returningClient"  checked="<? $checked ?>" onclick="javascript:Function_Name_2();"  />Returning Client
<?
}


?>




<br />
THIS IS MY DROP DOWN MENU TO DISPLAY.<br />


<select>
<option>Seleccionar</option>
<option value="Casa" onclick="javascript:Function_Name();"><a href="#">New Client</a></option>
<option value="Casa" onclick="javascript:Function_Name_2();"><a href="#">Returning Client</a></option>
</select><br />



THIS IS MY BUTTON TO DISPLAY MY FUNCTION BLOCK!<br />
<!--THIS IS USING THE CSS CLASS FOR YOUR BUTTON UP AT THE TOP AND THE JAVA SCRIPT onclick AT THE BOTTOM-->
<span class="About"  onclick="javascript:Function_Name();"><a href="#"></a></span><br />


<!--THIS IS USING THE CSS CLASS FOR YOUR BUTTON UP AT THE TOP AND THE JAVA SCRIPT onclick AT THE BOTTOM-->
<span class="AboutMore"  onclick="javascript:Function_Name_2();"><a href="#"></a></span><br />


<div id="myfuction" style="display: none;padding: 5px;">
THIS IS MY FUCTION TEST BLOCK I WANT TO DISPLAY! NEW CLIENT

</div>
<div id="myfuction_2" style="display: none;padding: 5px;">
THIS IS MY FUCTION TEST BOCK 2 I WANT TO DISPLAY!  RETURNING CLIENT
</div>
<script type="text/javascript">
function Function_Name() 
 {
  if(document.getElementById('myfuction').style.display=='none')
  {
   //THIS IS SHOWING THE DIV TAG 
           div = document.getElementById('myfuction');
           div.style.display = "block";

  //THIS IS HIDING THE OTHER DIV TAG AND ONLY SHOWING YOU THE ONE
  div = document.getElementById('myfuction_2');
           div.style.display = "none";


  }
  else
  {
   //THIS IS HIDING THE DIV TAG IF YOU CLICK IT TWICE IT OPENS IT SHUTS 
   div = document.getElementById('myfuction');
           div.style.display = "none";
  }

       }
 function Function_Name_2() 
 {
  if(document.getElementById('myfuction_2').style.display=='none')
  {
   //THIS IS SHOWING THE DIV TAG 
           div = document.getElementById('myfuction_2');
           div.style.display = "block";
  //THIS IS HIDING THE OTHER DIV TAG AND ONLY SHOWING YOU THE ONE
  div = document.getElementById('myfuction');
           div.style.display = "none";


  }
  else
  {
   //THIS IS HIDING THE DIV TAG IF YOU CLICK IT TWICE IT OPENS IT SHUTS 
   div = document.getElementById('myfuction_2');
           div.style.display = "none";
  }

       }
</script>

Well couldn't he place the form tags in a div tags

 

he has 4 forms tags and he wants to put it all in one? I think that's what hes saying.

 

How can i remove the form tags when i call the form by renderPartial? I have 4 forms from dixx views and i want to combine them into one sinlge form so when i cal render partial form tags should not be included.

 

thanks in advance

 

 

<form id="one">

</form>

 

<form id="two">

</form>

 

<form id="three">

</form>

 

<form id="four">

</form>

 

i say if statements

 

is it php?

 

it has to be simple. but I don't see any code to understand what hes doing.

I would just call the tag when i need it, and if it changes call another.

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.