Converting A Block Of Vb6 To Php

[KenHorse]

I am new to PHP but have been programming in VB6 for many years. I have the following code I'm trying to convert to PHP and I've figured most of it out but am stuck on one line that I can't find an equivalent way to do in PHP (it is a VERY simple encryption scheme I know but I cannot change it). My plan is for a webform to supply the Username and callsign but for testing purposes, I'm assigning those variables.

 

Here's the VB6 code:

Username = "Peter Piper"
CallSign = "aa4aa"

CallSign = UCase(CallSign) 'force uppercase callsign

If Len(Username) Then
For A = 1 To Len(CallSign)
 B = Asc(Mid(CallSign, A, 1))
 B = B + Asc(Mid(Username, (A Mod Len(Username)) + 1, 1))
 strBuff = strBuff & Chr$(B And &HFF)
Next
Else
 strBuff = CallSign
End If

 

And here's what I've come up with (so far) in PHP:

 

$username = "Peter Piper;
$callsign = "aa4aa" ;

$uppercase = strtoupper($callsign) ;
$callsign = $uppercase ;
$datalen = strlen($username) ;

//Encrypt string

If($datalen > 0) {

 For($A=1; $A<=$datalen; $A++)
 {
 $B = substr($callsign, $A, 1) ; // get one character at a time
 $B = ord($B) ; // convert to ASCII	


 }

}

 

Thanks in advance

Edited December 2, 2012 by KenHorse

[DavidAM]

Ahh, VB6! Takes me back to my younger days ...

 

I think this would do it.

$Username = "Peter Piper";
$CallSign = "aa4aa";

$CallSign = strtoupper($CallSign); #force uppercase callsign

If strlen($Username) {    ## or use: if (! empty($Username))
   $strBuff = '';    ## Avoid an undefined variable Notice later
   for ($A = 0; $A < strlen($CallSign); $A++) { ## NOTE Start at Zero NOT One
       $B = ord(substr($CallSign, $A, 1));
       $B = $B + ord(substr($Username, ($A % strlen($Username)) + 1, 1));    ## % is Mod
       $strBuff = $strBuff . Chr($B & &HFF);    ## NOTE concatenation is . (dot) // & is bitwise And
   }
} Else {
   $strBuff = $CallSign;
} 

 

That could be optimized a bit, but I wanted to keep it as close to the original code as possible so you can see the differences. I added comments about some significant points

[KenHorse]

Thanks very much! But I am getting the following error:

 

Parse error: syntax error, unexpected '&' in encrypt.php on line 22

 

which is this line:

 

$strBuff = $strBuff . Chr($B & &HFF);

 

 

EDIT: Found the problem. Apparently &HFF isn't legal syntax in PHP, so I changed the line to:

 

$strBuff = $strBuff . Chr($B & 255);

 

and it's good

Edited December 2, 2012 by KenHorse

[DavidAM]

Sorry, you're right. It should be $strBuff = $strBuff . Chr($B & 0xFF);

[KenHorse]

Sorry, you're right. It should be $strBuff = $strBuff . Chr($B & 0xFF);

 

No problem. I really appeciate your help