NiallFH Posted December 5, 2012 Share Posted December 5, 2012 (edited) Hi all, first time poster here, but long time beginner using PHP and MySQL to put together sports statistics sites. The one I'm working on just now has me befuddled. I've never really worked with dates in MySQL before, so this is new territory for me, but I've been reading into DATEDIFF to try to achieve the following: I have two tables. One with a list of players and one with a list of goals scored. What I want to display is ONE result for the player who was the YOUNGEST scorer of a goal. Within the tables, I have: PlayerID | PlayerName | PlayerDOB GoalID | GoalPlayerID | GoalMatchDate So, I'm assuming we're looking at the DATEDIFF between the MIN(GoalMatchDate) and the PlayerDOB, while PlayerID = GoalPlayerID. That being said, I'm completely at a loss on how to start to query this, most specifically, in terms of limiting it to one query and how to order it by the difference in the dates. Hopefully someone can put me on the right track or even be so kind as to post an example that I could follow. Edited December 5, 2012 by NiallFH Quote Link to comment Share on other sites More sharing options...
NiallFH Posted December 5, 2012 Author Share Posted December 5, 2012 For clarification, I am using MySQL 5.0. Quote Link to comment Share on other sites More sharing options...
Barand Posted December 5, 2012 Share Posted December 5, 2012 try SELECT GoalMatchDate, playerDOB, playerName, DATEDIFF(GoalMatchDate, playerDOB) as age FROM goal g INNER JOIN player p ON g.GoalPlayerID = p.playerid ORDER BY age LIMIT 1; Quote Link to comment Share on other sites More sharing options...
NiallFH Posted December 5, 2012 Author Share Posted December 5, 2012 try SELECT GoalMatchDate, playerDOB, playerName, DATEDIFF(GoalMatchDate, playerDOB) as age FROM goal g INNER JOIN player p ON g.GoalPlayerID = p.playerid ORDER BY age LIMIT 1; Thanks for that Barand. This works a treat! I have a related question however - is there a way to rearrange the format of the days into years, months and days? Quote Link to comment Share on other sites More sharing options...
Muddy_Funster Posted December 5, 2012 Share Posted December 5, 2012 my suggestion would be SELECT GoalMatchDate, playerDOB, playerName, DATEDIFF(GoalMatchDate, playerDOB) as age, DATE_FORMAT(FROM_DAYS(DATEDIFF(GoalMatchDate, playerDOB)),'%yYears, %mMonth(s) and %dDays') as displayAge FROM goal g INNER JOIN player p ON g.GoalPlayerID = p.playerid ORDER BY age LIMIT 1; This way you get a formated field for display and a numerical field for accurate sorting. Quote Link to comment Share on other sites More sharing options...
Barand Posted December 5, 2012 Share Posted December 5, 2012 I tried FROM_DAYS() but it doesn't give accurate results. In my test data below it should give 20 years 10 months, however Match_date | PlayerDOB | Name | Days | FROM_DATE 2012-02-01 | 1991-04-01| Harry | 7611 | 0020-11-02 You would be better with a custom function eg function YMDdiff($date1, $date2) { list($y1, $m1, $d1) = sscanf($date1, '%d-%d-%d'); list($y2, $m2, $d2) = sscanf($date2, '%d-%d-%d'); $diff = array('y'=>0, 'm'=>0, 'd'=>0); if ($d1 < $d2) { $d1 += date('t', mktime(0,0,0,$m2,1,$y2)); $m2++; } $diff['d'] = $d1 - $d2; if ($m1 < $m2) { $m1 += 12; $y2++; } $diff['m'] = $m1 - $m2; $diff['y']= $y1 - $y2; return ($diff['y'] ? "{$diff['y']} years " : '') . ($diff['m'] ? "{$diff['m']} months " : '') . ($diff['d'] ? "{$diff['d']} days " : ''); } echo YMDdiff('2012-02-01', '1991-04-01'); // --> 20 years 10 months Quote Link to comment Share on other sites More sharing options...
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