Menu Script

[PFMaBiSmAd]

If you change this code -

while($result = mysql_fetch_assoc($query){
 $startList[] = $result;
}

 

To this -

while($result = mysql_fetch_assoc($query){
 $refactorList[$result['assoc_menu']][] = $result;
}

 

you can eliminate that entire middle loop.

 

 

To detect if there's only one item in the menu, inside the last foreach(){} loop, you would test how many entires are in the $menu array using count and decide if you need to output the link as a button or loop over the $menu array and output it as the drop-down menu (the existing contents of that foreach(){} loop.)

Edited December 29, 2012 by PFMaBiSmAd

[JakkkeM]

Still null.

 

Why is this so difficult?!

[JakkkeM]

Managed to get a working solution.

 

Had my friend make up an OOP Code...