PHP Array inside of a function

[admiralgeek]

Hi, I am trying to output an array inside of an function but all I get is one out put, it is as if the foreach loop is not working. Any help?

 

 <?php
function writeValue($value)
{
$PCR=array($value);

foreach($PCR as $value) {
 echo $value;
}

}

?>  

<?php writeValue("one","two","three","ect") ?>

[gristoi]

it is because you are only expecting the first parameter ("one") to be passed in the function

function writeValue(array $value)
{
foreach($value as $output)
{
print $output.PHP_EOL;
}
}
<?php
writeValue(array('one','two','three','four'));

.

[Barand]

or you can use func_get_args if you want to send them as separate values

[admiralgeek]

Thank you, I had to replace PHP_EOL with html formatted <br />, in order for each value to have a newline.

[PaulRyan]

You shouldn't really echo or print from a function as it doesn't do as you expect.

 

Return the value from the function and assign it to a variable, then use that variable to display its value.

 

<?PHP
function writeValue($value) {
//### Check to make sure an array was provided
if(!is_array($value)) {
 $finalOutput = 'You did not provide an array.';
//### If an array is provided add each element to the output
} else {
 $finalOutput = '';

 //### Foreach element add it to the output
 foreach($value AS $output) {
 $finalOutput .= $output . PHP_EOL;
 }
}
//### Return the output, don't echo
return $finalOutput;
}
//### Echo output from function
$functionOutput = writeValue(array('one','two','three','four'));
echo nl2br($functionOutput);
?>

Edited January 23, 2013 by PaulRyan