PHP gd - image alpha(ing)

[helppy]

I am faced with problems using php gd as i am doing some image manuplication.

I am actually trying to display an image (e.g 800*600) as the main display then having a photo (e.g 100*70) on top on it, with a starting co-ordinate points of (0,0).

I am able to display the photo on top of it but am unable to alpha the photo so that the display area behind the photo is visible too.

does anyone knows how to solve my problem?

Thanks.

[printf]

Sure it can be done, could you show me your script so I can tell you what you need to change...

[helppy]

<?php

$im_a = @imagecreatefrompng("images/Water lilies.png");

//$im_b = @imagecreatefrompng("images/SunsetEDIT.png");

$im_b_x = 10;
$im_b_y = 10;

$im_b = imagecolorallocatealpha($im_a, 0, 0, 0, 50);
imagefilledrectangle($im_a, 0, 0, 100, 100 , $im_b);

//$im_c = imagecolorallocatealpha($im_a, 255, 0, 0, 50);
//imagefilledrectangle($im_a, 0, 0, 200, 200 , $im_c);

header("Content-type: image/png");
imagepng($im_a);

?>

--------------------------------------------------------------------------------------------

<?php

$adImage = ImageCreateFromJPEG('images/Water lilies.jpg');
ImageAlphaBlending($adImage, true);

$photoImage = ImageCreateFromJPEG('images/top.jpg');
//$photoImage = imagecolorallocatealpha($adImage, 0, 255, 0, 50);
$logoW = ImageSX($photoImage);
$logoH = ImageSY($photoImage);

ImageCopy($adImage, $photoImage, 0, 0, 0, 0, $logoW, $logoH);

//output to browser
ImageJPEG($adImage);

ImageDestroy($adImage);
ImageDestroy($photoImage);

?>

--------------------------------------------------------------------------------------------

Both have different output:
First one, it has alpha but its a drawn rectangle.
Second one, has photo overlap but not alpha.

The output i hope to get is the combining of both - photo that is being alpha.

thanks!!!