DT107 Posted March 2, 2013 Share Posted March 2, 2013 (edited) Hi I am working on a job board and have two tables members and jobs. How can I join the two using foreign keys. Here is the members table CREATE TABLE `members` ( `id` int(4) NOT NULL auto_increment, `username` varchar(65) NOT NULL default '', `password` varchar(65) NOT NULL default '', PRIMARY KEY (`id`) ) TYPE=MyISAM AUTO_INCREMENT=2 ; Here is the jobs table CREATE TABLE IF NOT EXISTS `Jobs` ( `id` int(11) NOT NULL auto_increment, `Job_Title` varchar(50) NOT NULL, `Company` varchar(50) NOT NULL, `Salary` varchar(50) NOT NULL, `Description` varchar(500) NOT NULL, `Phone_Number` varchar(50) NOT NULL, `Requirements` varchar(200) NOT NULL, `Job_Category` varchar(50) NOT NULL, `Job_Type` varchar(50) NOT NULL, `Email` varchar(50) NOT NULL, `State` varchar(50) NOT NULL, `Address` varchar(50) NOT NULL, `Country` varchar(50) NOT NULL, `Zipcode` varchar(12) NOT NULL, `City` varchar(50) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=9 ; Thanks DT107 Edited March 3, 2013 by fenway Quote Link to comment Share on other sites More sharing options...
Barand Posted March 2, 2013 Share Posted March 2, 2013 What foreign key? Quote Link to comment Share on other sites More sharing options...
DT107 Posted March 2, 2013 Author Share Posted March 2, 2013 I found an article but not sure how to apply it to my situation. Here is the article. http://www.sitepoint.com/mysql-foreign-keys-quicker-database-development/ Quote Link to comment Share on other sites More sharing options...
trq Posted March 2, 2013 Share Posted March 2, 2013 How would we know how to apply it to your situation if you dont? Describe the relationship you are looking to create. Quote Link to comment Share on other sites More sharing options...
DT107 Posted March 3, 2013 Author Share Posted March 3, 2013 I would like users to create an account and be able to post jobs on the site and also be able to edit only the jobs that they post. Thanks DT107 Quote Link to comment Share on other sites More sharing options...
trq Posted March 3, 2013 Share Posted March 3, 2013 So you need to add a `member_id` column to your Jobs table. Quote Link to comment Share on other sites More sharing options...
DT107 Posted March 3, 2013 Author Share Posted March 3, 2013 can you please give an example of how to do this ? Thanks DT107 Quote Link to comment Share on other sites More sharing options...
DT107 Posted March 3, 2013 Author Share Posted March 3, 2013 (edited) I have added a members colum to the jobs. Here is what I have so far. CREATE TABLE IF NOT EXISTS `Jobs` ( `id` int(11) NOT NULL auto_increment, `Job_Title` varchar(50) NOT NULL, `Company` varchar(50) NOT NULL, `Salary` varchar(50) NOT NULL, `Description` varchar(500) NOT NULL, `Phone_Number` varchar(50) NOT NULL, `Requirements` varchar(200) NOT NULL, `Job_Category` varchar(50) NOT NULL, `Job_Type` varchar(50) NOT NULL, `Email` varchar(50) NOT NULL, `State` varchar(50) NOT NULL, `Address` varchar(50) NOT NULL, `Country` varchar(50) NOT NULL, `Zipcode` varchar(12) NOT NULL, `City` varchar(50) NOT NULL, PRIMARY KEY (`id`), FOREIGN KEY (Members_ID) REFERENCES Persons(Members_ID) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=9 ; Am doing it the correct way ? Thanks DT107 Edited March 3, 2013 by fenway Quote Link to comment Share on other sites More sharing options...
trq Posted March 3, 2013 Share Posted March 3, 2013 can you please give an example of how to do this ?You just linked to an article. What part of that article do you not understand in particular?I have added a members colum to the jobs.I don't see any column to store the member id. Forget the FOREIGN KEY contraints for now, in a simple example they are not needed. Just add a member_id column to your jobs table, then store the id from the member table within this member_id column. This column is then used to JOIN the tables in SELECT queries. Quote Link to comment Share on other sites More sharing options...
DT107 Posted March 3, 2013 Author Share Posted March 3, 2013 (edited) How about this I have modified the two tables. Here is modified members table: CREATE TABLE `members` ( `id` int(4) NOT NULL auto_increment, `username` varchar(65) NOT NULL default '', `password` varchar(65) NOT NULL default '', `Members_ID` varchar(65) NOT NULL auto_increment, '' PRIMARY KEY (`id`) ) TYPE=MyISAM AUTO_INCREMENT=2 ; Here is modified jobs table: CREATE TABLE IF NOT EXISTS `Jobs` ( `id` int(11) NOT NULL auto_increment, `Job_Title` varchar(50) NOT NULL, `Company` varchar(50) NOT NULL, `Salary` varchar(50) NOT NULL, `Description` varchar(500) NOT NULL, `Phone_Number` varchar(50) NOT NULL, `Requirements` varchar(200) NOT NULL, `Job_Category` varchar(50) NOT NULL, `Job_Type` varchar(50) NOT NULL, `Email` varchar(50) NOT NULL, `State` varchar(50) NOT NULL, `Address` varchar(50) NOT NULL, `Country` varchar(50) NOT NULL, `Zipcode` varchar(12) NOT NULL, `City` varchar(50) NOT NULL, PRIMARY KEY (`id`), FOREIGN KEY (Members_ID) REFERENCES Members(Members_ID) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=9 ; Edited March 3, 2013 by fenway Quote Link to comment Share on other sites More sharing options...
mikosiko Posted March 3, 2013 Share Posted March 3, 2013 Stop using the keyboard and read carefully what trq posted for you.. what you did is not even close. As he recomend you forget about the foreign key constraint and focus in the data y relationships that you want to implement firts... in a side note, foreing key in MyIsam engine are not enforced at all.. so... Quote Link to comment Share on other sites More sharing options...
DT107 Posted March 5, 2013 Author Share Posted March 5, 2013 Hi Everyone, Thanks for your help I found a great article that explains more easily with examples. http://www.sitepoint.com/mysql-foreign-keys-quicker-database-development/ regards, DT7 Quote Link to comment Share on other sites More sharing options...
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